Find the difference quotient of $LaTeX: \displaystyle f(x)=6 x^{3} - 10 x^{2} + 2 x - 10$ .

The difference quotient is $LaTeX: \displaystyle \frac{f(x+h)-f(x)}{h}$ . Evaluating $LaTeX: \displaystyle f(x+h)=2 h + 2 x + 6 \left(h + x\right)^{3} - 10 \left(h + x\right)^{2} - 10$ and expanding gives $LaTeX: \displaystyle f(x+h)=6 h^{3} + 18 h^{2} x - 10 h^{2} + 18 h x^{2} - 20 h x + 2 h + 6 x^{3} - 10 x^{2} + 2 x - 10$ Evaluating the difference quotient gives $LaTeX: \displaystyle \frac{(6 h^{3} + 18 h^{2} x - 10 h^{2} + 18 h x^{2} - 20 h x + 2 h + 6 x^{3} - 10 x^{2} + 2 x - 10)-(6 x^{3} - 10 x^{2} + 2 x - 10)}{h}$ Simplifying gives $LaTeX: \displaystyle \frac{6 h^{3} + 18 h^{2} x - 10 h^{2} + 18 h x^{2} - 20 h x + 2 h}{h}=6 h^{2} + 18 h x - 10 h + 18 x^{2} - 20 x + 2$