Solve. $LaTeX: \displaystyle \sqrt{x + 32}=\sqrt{x - 8} - 1$

Squaring both sides gives $LaTeX: \displaystyle x + 32=x - 2 \sqrt{x - 8} - 7$ . Isolating the radical gives $LaTeX: \displaystyle - \frac{39}{2}=\sqrt{x - 8}$ Squaring again gives $LaTeX: \displaystyle \frac{1521}{4}=x - 8$ . Solving for $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x=\frac{1553}{4}$ . Checking the solution, $LaTeX: \displaystyle x = \frac{1553}{4}$ , in the original equation gives $LaTeX: \displaystyle \frac{41}{2} = \frac{37}{2}$ which is false so it is an extraneous solution and there is no solution.