Find the local maximum and minimum of $LaTeX: \displaystyle f(x) = - x^{3} - 4 x^{2} - 5 x + 2$ .

To find the critical numbers solve $LaTeX: \displaystyle f'(x) = 0$ . The derivative is $LaTeX: \displaystyle f'(x) = - 3 x^{2} - 8 x - 5$ . Solving $LaTeX: \displaystyle - 3 x^{2} - 8 x - 5 = 0$ gives $LaTeX: \displaystyle x = \left[ - \frac{5}{3}, \ -1\right]$ . Using the 2nd derivative test gives:
$LaTeX: \displaystyle f''\left( - \frac{5}{3} \right) = 2$ which is greater than zero, so the function is concave up and $LaTeX: \displaystyle f\left(- \frac{5}{3}\right) = \frac{104}{27}$ is a local minimum.
$LaTeX: \displaystyle f''\left( -1 \right) = -2$ which is less than zero, so the function is concave down and $LaTeX: \displaystyle f\left(-1\right) = 4$ is a local maximum.