Factor $LaTeX: \displaystyle 36 x^{3} + 9 x^{2} + 32 x + 8$ .

Grouping the first two terms and factoring out their GCF, $LaTeX: \displaystyle 9 x^{2}$ , gives $LaTeX: \displaystyle 9 x^{2}(4 x + 1)$ . Grouping the last two terms and factoring out their GCF, $LaTeX: \displaystyle 8$ , gives $LaTeX: \displaystyle 8(4 x + 1)$ . The polynomial now has a common binomial factor of $LaTeX: \displaystyle 4 x + 1$ . This gives $LaTeX: \displaystyle 9 x^{2} \left(4 x + 1\right) +8 \cdot \left(4 x + 1\right) = \left(4 x + 1\right) \left(9 x^{2} + 8\right)$ .