Use the discriminant, $LaTeX: \displaystyle b^2-4ac$ to determine the number and type of solutions to the equation $LaTeX: \displaystyle - 6 x^{2} + x - 3 = 0$ . No points will be given if the discriminant is not used.

Since the discriminant is $LaTeX: \displaystyle b^2-4ac=(1)^2-4(-6)(-3)=-71$ and is negative, the equation has two imaginary solutions.