$14000 is invested in two different accounts. One account pays 14% simple interest per year and the other account pays 26% simple interest per year. If the total interest earn in one year is $3100.00, how much is invested at each rate?

Let $LaTeX: \displaystyle x$ be the amount invested at 14%. Then $LaTeX: \displaystyle 14000-x$ is amount invested at 26%. This gives the equation $LaTeX: \displaystyle 0.14 x+0.26(14000 - x)=3100$ . Solving for $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x = 4500$ . So the amount in the other account is $9500.