Solve the inequality $LaTeX: \displaystyle \frac{8}{x^{2} - 9}<\frac{9}{x^{2} + 8 x + 15}$

Getting zero on one side and factoring gives $LaTeX: \displaystyle - \frac{9}{\left(x + 3\right) \left(x + 5\right)} + \frac{8}{\left(x - 3\right) \left(x + 3\right)}< 0$ . This gives the least common denominator as $LaTeX: \displaystyle \left(x - 3\right) \left(x + 3\right) \left(x + 5\right)$ . Building each fraction to get the common denominator gives $LaTeX: \displaystyle \frac{8 x + 40 - (9 x - 27)}{\left(x - 3\right) \left(x + 3\right) \left(x + 5\right)} < 0$ . Simplifying gives $LaTeX: \displaystyle \frac{67 - x}{\left(x - 3\right) \left(x + 3\right) \left(x + 5\right)}<0$ . The inequality can change signs at the zeros of the numerator, $LaTeX: \displaystyle \left\{67\right\}$ , or the zeros of the denominator $LaTeX: \displaystyle \left\{-5, -3, 3\right\}$ . Making a sign chart gives: This gives the solution $LaTeX: \displaystyle \left(-\infty, -5\right) \cup \left(-3, 3\right) \cup \left(67, \infty\right)$