Suppose that $14141 is invested at an interest rate of 18% per year, compounded continuously. What is the account balance after 30 years?

Using LaTeX:  \displaystyle P=P_0e^{kt} gives LaTeX:  \displaystyle P=14141e^{\frac{9 t}{50}} . Evaluating at LaTeX:  \displaystyle t=30 gives LaTeX:  \displaystyle P=3130908 dollars.