Solve the inequality $LaTeX: \displaystyle \frac{5}{x^{2} - 9}<\frac{4}{x^{2} - 4 x + 3}$

Getting zero on one side and factoring gives $LaTeX: \displaystyle \frac{5}{\left(x - 3\right) \left(x + 3\right)} - \frac{4}{\left(x - 3\right) \left(x - 1\right)}< 0$ . This gives the least common denominator as $LaTeX: \displaystyle \left(x - 3\right) \left(x - 1\right) \left(x + 3\right)$ . Building each fraction to get the common denominator gives $LaTeX: \displaystyle \frac{5 x - 5 - (4 x + 12)}{\left(x - 3\right) \left(x - 1\right) \left(x + 3\right)} < 0$ . Simplifying gives $LaTeX: \displaystyle \frac{x - 17}{\left(x - 3\right) \left(x - 1\right) \left(x + 3\right)}<0$ . The inequality can change signs at the zeros of the numerator, $LaTeX: \displaystyle \left\{17\right\}$ , or the zeros of the denominator $LaTeX: \displaystyle \left\{-3, 1, 3\right\}$ . Making a sign chart gives: This gives the solution $LaTeX: \displaystyle \left(-3, 1\right) \cup \left(3, 17\right)$