Two dice are rolled. Find the probability that the sum is greater than 8 or that one die is less than 5.

There are 10 ways the sum is greater than 8. There are 32 ways one die is less than 5. The events are not mutually exclusive and they occur simultaneously 6 times. Using the formula $LaTeX: P(A \cup B) = P(A) + P(B) - P(A \cap B) = \frac{5}{18} + \frac{8}{9} - \frac{1}{6} = 1$