Use $LaTeX: \displaystyle a_1=-6$ and $LaTeX: \displaystyle a_2=2$ and $LaTeX: \displaystyle a_n=-6a_{n-1} -4a_{n-2}$ to find $LaTeX: \displaystyle a_{9}$

Finding the next term in the sequence gives $LaTeX: \displaystyle a_3=(-6)(-6)+(-4)(2)=28$
$LaTeX: \displaystyle a_{4}=(-6)(2)+(-4)(28)=-124$ .
$LaTeX: \displaystyle a_{5}=(-6)(28)+(-4)(-124)=328$ .
$LaTeX: \displaystyle a_{6}=(-6)(-124)+(-4)(328)=-568$ .
$LaTeX: \displaystyle a_{7}=(-6)(328)+(-4)(-568)=304$ .
$LaTeX: \displaystyle a_{8}=(-6)(-568)+(-4)(304)=2192$ .
$LaTeX: \displaystyle a_{9}=(-6)(304)+(-4)(2192)=-10592$ .