Solve the inequality $LaTeX: \displaystyle \frac{6}{x^{2} - 25}<\frac{5}{x^{2} + x - 20}$

Getting zero on one side and factoring gives $LaTeX: \displaystyle - \frac{5}{\left(x - 4\right) \left(x + 5\right)} + \frac{6}{\left(x - 5\right) \left(x + 5\right)}< 0$ . This gives the least common denominator as $LaTeX: \displaystyle \left(x - 5\right) \left(x - 4\right) \left(x + 5\right)$ . Building each fraction to get the common denominator gives $LaTeX: \displaystyle \frac{6 x - 24 - (5 x - 25)}{\left(x - 5\right) \left(x - 4\right) \left(x + 5\right)} < 0$ . Simplifying gives $LaTeX: \displaystyle \frac{x + 1}{\left(x - 5\right) \left(x - 4\right) \left(x + 5\right)}<0$ . The inequality can change signs at the zeros of the numerator, $LaTeX: \displaystyle \left\{-1\right\}$ , or the zeros of the denominator $LaTeX: \displaystyle \left\{-5, 4, 5\right\}$ . Making a sign chart gives: This gives the solution $LaTeX: \displaystyle \left(-5, -1\right) \cup \left(4, 5\right)$