Solve the equation $LaTeX: \displaystyle \log_{3}(x + 104)-\log_{3}(x + 50)=1$ .

Using the quotient property of logarithms gives $LaTeX: \displaystyle \log_{3}\frac{x + 104}{x + 50} = 1$ . Making both sides of the equation exponents on the base $LaTeX: \displaystyle 3$ gives $LaTeX: \displaystyle \frac{x + 104}{x + 50}=3$ . Clearing the fractions by multiplying by the LCD gives $LaTeX: \displaystyle x + 104=3 x + 150$ . Isolating $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x = -23$ .