Find the derivative of LaTeX:  \displaystyle y = \frac{\left(- 3 x - 8\right)^{7} e^{- x} \sin^{7}{\left(x \right)}}{\left(- 9 x - 4\right)^{6} \sqrt{\left(6 x + 4\right)^{3}}}

Taking the natural logarithm of both sides of the equation and expanding the right hand side gives: LaTeX:  \ln(y) = \ln{\left(\frac{\left(- 3 x - 8\right)^{7} e^{- x} \sin^{7}{\left(x \right)}}{\left(- 9 x - 4\right)^{6} \sqrt{\left(6 x + 4\right)^{3}}} \right)}   Expanding the right hand side using the product and quotient properties of logarithms gives: LaTeX:  \ln(y) = 7 \ln{\left(- 3 x - 8 \right)} + 7 \ln{\left(\sin{\left(x \right)} \right)}- x - 6 \ln{\left(- 9 x - 4 \right)} - \frac{3 \ln{\left(6 x + 4 \right)}}{2}   Taking the derivative on both sides of the equation yields: LaTeX:  \frac{y'}{y} = -1 + \frac{7 \cos{\left(x \right)}}{\sin{\left(x \right)}} - \frac{9}{6 x + 4} - \frac{21}{- 3 x - 8} + \frac{54}{- 9 x - 4}   Solving for LaTeX:  \displaystyle y' and substituting out y using the original equation gives LaTeX:  y' = \left(-1 + \frac{7 \cos{\left(x \right)}}{\sin{\left(x \right)}} - \frac{9}{6 x + 4} - \frac{21}{- 3 x - 8} + \frac{54}{- 9 x - 4}\right)\left(\frac{\left(- 3 x - 8\right)^{7} e^{- x} \sin^{7}{\left(x \right)}}{\left(- 9 x - 4\right)^{6} \sqrt{\left(6 x + 4\right)^{3}}} \right)   Using some Trigonometric identities to simplify gives LaTeX:  y' = \left(\frac{7}{\tan{\left(x \right)}} - \frac{21}{- 3 x - 8}-1 - \frac{9}{6 x + 4} + \frac{54}{- 9 x - 4}\right)\left(\frac{\left(- 3 x - 8\right)^{7} e^{- x} \sin^{7}{\left(x \right)}}{\left(- 9 x - 4\right)^{6} \sqrt{\left(6 x + 4\right)^{3}}} \right)