Solve $LaTeX: \displaystyle \log_{6}(x - 1)+\log_{6}(x + 4) = 2$ .

Using logarithmic properties and expanding the argument gives $LaTeX: \displaystyle \log_{6}(x^{2} + 3 x - 4)=2$ . Making both sides an exponent on the base gives $LaTeX: \displaystyle x^{2} + 3 x - 4=6^{2}$ . Expanding and setting equal to zero gives $LaTeX: \displaystyle x^{2} + 3 x - 40=0$ . Factoring gives $LaTeX: \displaystyle \left(x - 5\right) \left(x + 8\right)=0$ . Solving gives the two possible solutions $LaTeX: \displaystyle x = -8$ and $LaTeX: \displaystyle x = 5$ . The domain of the original is $LaTeX: \displaystyle \left(1, \infty\right) \bigcap \left(-4, \infty\right)=\left(1, \infty\right)$ . Checking if each possible solution is in the domain gives: $LaTeX: \displaystyle x = -8$ is not a solution. $LaTeX: \displaystyle x=5$ is a solution.