$14600 is invested in two different accounts. One account pays 13% simple interest per year and the other account pays 19% simple interest per year. If the total interest earn in one year is $2360.00, how much is invested at each rate?

Let $LaTeX: \displaystyle x$ be the amount invested at 13%. Then $LaTeX: \displaystyle 14600-x$ is amount invested at 19%. This gives the equation $LaTeX: \displaystyle 0.13 x+0.19(14600 - x)=2360$ . Solving for $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x = 6900$ . So the amount in the other account is $7700.