Use Simpson's rule to find the arclength of the curve $LaTeX: \displaystyle f(x)=\ln{\left(x \right)}$ on $LaTeX: \displaystyle (4,10)$ with $LaTeX: \displaystyle n=32$ .

$LaTeX: \displaystyle \Delta x = \frac{ 10 - 4 }{ 32 }$ . $LaTeX: \displaystyle x_i = a +i\Delta x = 4 + i \frac{3}{16}$ Using the 1,4,2,...,2,4,1 pattern the sum can be written as $LaTeX: \displaystyle x_i$ can be written split into the even and odd terms. $LaTeX: \displaystyle x_k = 4 + (2k-1)\cdot \frac{3}{16}$ for $LaTeX: \displaystyle k=1$ to $LaTeX: \displaystyle k =16$ and $LaTeX: \displaystyle x_j = 4 + (2j)\cdot \frac{3}{16}$ for $LaTeX: \displaystyle j=1$ to $LaTeX: \displaystyle j =15$ . $LaTeX: \displaystyle f(4) +f(10)+4\sum_{k=1}^{16}f\left(\frac{3 k}{8} + \frac{61}{16}\right) + 2\sum_{j=1}^{15}f\left(\frac{3 j}{8} + 4\right)$ . The value is $LaTeX: \displaystyle 6.0744$