Suppose that $4090 is invested at an interest rate of 10% per year, compounded continuously. What is the account balance after 11 years?

Using LaTeX:  \displaystyle P=P_0e^{kt} gives LaTeX:  \displaystyle P=4090e^{\frac{t}{10}} . Evaluating at LaTeX:  \displaystyle t=11 gives LaTeX:  \displaystyle P=12287 dollars.