Solve the equation $LaTeX: \displaystyle \log_{6}(x + 191)-\log_{6}(x + 11)=1$ .

Using the quotient property of logarithms gives $LaTeX: \displaystyle \log_{6}\frac{x + 191}{x + 11} = 1$ . Making both sides of the equation exponents on the base $LaTeX: \displaystyle 6$ gives $LaTeX: \displaystyle \frac{x + 191}{x + 11}=6$ . Clearing the fractions by multiplying by the LCD gives $LaTeX: \displaystyle x + 191=6 x + 66$ . Isolating $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x = 25$ .