Solve. $LaTeX: \displaystyle \sqrt{x + 32}=\sqrt{x - 4} - 1$

Squaring both sides gives $LaTeX: \displaystyle x + 32=x - 2 \sqrt{x - 4} - 3$ . Isolating the radical gives $LaTeX: \displaystyle - \frac{35}{2}=\sqrt{x - 4}$ Squaring again gives $LaTeX: \displaystyle \frac{1225}{4}=x - 4$ . Solving for $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x=\frac{1241}{4}$ . Checking the solution, $LaTeX: \displaystyle x = \frac{1241}{4}$ , in the original equation gives $LaTeX: \displaystyle \frac{37}{2} = \frac{33}{2}$ which is false so it is an extraneous solution and there is no solution.