Use the discriminant, $LaTeX: \displaystyle b^2-4ac$ to determine the number and type of solutions to the equation $LaTeX: \displaystyle - 9 x^{2} - 10 x + 8 = 0$ . No points will be given if the discriminant is not used.

Since the discriminant is $LaTeX: \displaystyle b^2-4ac=(-10)^2-4(-9)(8)=388$ and is positive, the equation has two real solutions.