Solve. $LaTeX: \displaystyle \sqrt{x + 32}=\sqrt{x - 6} + 2$

Squaring both sides gives $LaTeX: \displaystyle x + 32=x + 4 \sqrt{x - 6} - 2$ . Isolating the radical gives $LaTeX: \displaystyle \frac{17}{2}=\sqrt{x - 6}$ Squaring again gives $LaTeX: \displaystyle \frac{289}{4}=x - 6$ . Solving for $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x=\frac{313}{4}$ . Checking the solution, $LaTeX: \displaystyle x = \frac{313}{4}$ , in the original equation gives $LaTeX: \displaystyle \frac{21}{2} = \frac{21}{2}$ which is true so the solution checks.