Solve the equation $LaTeX: \displaystyle \log_{8}(x + 32787)-\log_{8}(x + 4115)=1$ .

Using the quotient property of logarithms gives $LaTeX: \displaystyle \log_{8}\frac{x + 32787}{x + 4115} = 1$ . Making both sides of the equation exponents on the base $LaTeX: \displaystyle 8$ gives $LaTeX: \displaystyle \frac{x + 32787}{x + 4115}=8$ . Clearing the fractions by multiplying by the LCD gives $LaTeX: \displaystyle x + 32787=8 x + 32920$ . Isolating $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x = -19$ .