Solve the equation $LaTeX: \displaystyle \log_{3}(x + 262)-\log_{3}(x + 28)=3$ .

Using the quotient property of logarithms gives $LaTeX: \displaystyle \log_{3}\frac{x + 262}{x + 28} = 3$ . Making both sides of the equation exponents on the base $LaTeX: \displaystyle 3$ gives $LaTeX: \displaystyle \frac{x + 262}{x + 28}=27$ . Clearing the fractions by multiplying by the LCD gives $LaTeX: \displaystyle x + 262=27 x + 756$ . Isolating $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x = -19$ .