Use the simplex method to maximize LaTeX:  \displaystyle p = 5 x + 17 y subject to LaTeX:  \displaystyle \begin{cases}53 x + 33 y \leq 1749 \\ 10 x + 83 y \leq 830 \\x \geq 0, y \geq 0 \end{cases}

Adding the slack variables LaTeX:  \displaystyle s and LaTeX:  \displaystyle t to the inequalities gives:
LaTeX:  \begin{cases}53 x + 33 y +s = 1749 \\ 10 x + 83 y+t = 830 \\ - 5 x - 17 y+p =0 \end{cases} This gives the first tableau:\begin{tabular}{|c|c|c|c|c|c|c|}\hline LaTeX:  \displaystyle  & LaTeX:  \displaystyle x & LaTeX:  \displaystyle y & LaTeX:  \displaystyle s & LaTeX:  \displaystyle t & LaTeX:  \displaystyle p & LaTeX:  \displaystyle  \\ \hline LaTeX:  \displaystyle s & LaTeX:  \displaystyle 53 & LaTeX:  \displaystyle 33 & LaTeX:  \displaystyle 1 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 1749 \\ \hline LaTeX:  \displaystyle t & LaTeX:  \displaystyle 10 & LaTeX:  \displaystyle 83 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 1 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 830 \\ \hline LaTeX:  \displaystyle p & LaTeX:  \displaystyle -5 & LaTeX:  \displaystyle -17 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 1 & LaTeX:  \displaystyle 0 \\ \hline \end{tabular}
The pivot row is LaTeX:  \displaystyle t and the pivot column is LaTeX:  \displaystyle y . The departing variable is LaTeX:  \displaystyle t and the incoming variable is LaTeX:  \displaystyle y . Pivoting using the row operations:
LaTeX:  \displaystyle 83R_1-33R_2
LaTeX:  \displaystyle 83R_3+17R_2
\begin{tabular}{|c|c|c|c|c|c|c|}\hline LaTeX:  \displaystyle  & LaTeX:  \displaystyle x & LaTeX:  \displaystyle y & LaTeX:  \displaystyle s & LaTeX:  \displaystyle t & LaTeX:  \displaystyle p & LaTeX:  \displaystyle  \\ \hline LaTeX:  \displaystyle s & LaTeX:  \displaystyle 4069 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 83 & LaTeX:  \displaystyle -33 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 117777 \\ \hline LaTeX:  \displaystyle y & LaTeX:  \displaystyle 10 & LaTeX:  \displaystyle 83 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 1 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 830 \\ \hline LaTeX:  \displaystyle p & LaTeX:  \displaystyle -245 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 17 & LaTeX:  \displaystyle 83 & LaTeX:  \displaystyle 14110 \\ \hline \end{tabular}
The pivot row is LaTeX:  \displaystyle s and the pivot column is LaTeX:  \displaystyle x . The departing variable is LaTeX:  \displaystyle s and the incoming variable is LaTeX:  \displaystyle x . Pivoting using the row operations:
LaTeX:  \displaystyle 4069R_2-10R_1
LaTeX:  \displaystyle 4069R_3+245R_1
\begin{tabular}{|c|c|c|c|c|c|c|}\hline LaTeX:  \displaystyle  & LaTeX:  \displaystyle x & LaTeX:  \displaystyle y & LaTeX:  \displaystyle s & LaTeX:  \displaystyle t & LaTeX:  \displaystyle p & LaTeX:  \displaystyle  \\ \hline LaTeX:  \displaystyle x & LaTeX:  \displaystyle 4069 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 83 & LaTeX:  \displaystyle -33 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 117777 \\ \hline LaTeX:  \displaystyle y & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 337727 & LaTeX:  \displaystyle -830 & LaTeX:  \displaystyle 4399 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 2199500 \\ \hline LaTeX:  \displaystyle p & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 0 & LaTeX:  \displaystyle 20335 & LaTeX:  \displaystyle 61088 & LaTeX:  \displaystyle 337727 & LaTeX:  \displaystyle 86268955 \\ \hline \end{tabular}
There are no negative values in row LaTeX:  \displaystyle p and this is the final tableau.The value of LaTeX:  \displaystyle x is LaTeX:  \displaystyle \frac{117777}{4069} . The value of LaTeX:  \displaystyle y is LaTeX:  \displaystyle \frac{26500}{4069} . The max value is LaTeX:  \displaystyle p = \frac{1039385}{4069}