Solve. $LaTeX: \displaystyle \sqrt{x + 28}=\sqrt{x + 2} + 4$

Squaring both sides gives $LaTeX: \displaystyle x + 28=x + 8 \sqrt{x + 2} + 18$ . Isolating the radical gives $LaTeX: \displaystyle \frac{5}{4}=\sqrt{x + 2}$ Squaring again gives $LaTeX: \displaystyle \frac{25}{16}=x + 2$ . Solving for $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x=- \frac{7}{16}$ . Checking the solution, $LaTeX: \displaystyle x = - \frac{7}{16}$ , in the original equation gives $LaTeX: \displaystyle \frac{21}{4} = \frac{21}{4}$ which is true so the solution checks.