Suppose that $8379 is invested at an interest rate of 24% per year, compounded continuously. What is the account balance after 43 years?

Using LaTeX:  \displaystyle P=P_0e^{kt} gives LaTeX:  \displaystyle P=8379e^{\frac{6 t}{25}} . Evaluating at LaTeX:  \displaystyle t=43 gives LaTeX:  \displaystyle P=254162365 dollars.