Write the function $LaTeX: \displaystyle f(x)=x^{2} - 16 x + 50$ in vertex form and identify the vertex.

$LaTeX: \displaystyle h = -\frac{b}{2a}$ and $LaTeX: \displaystyle k=f(h)$ . Using each formula gives $LaTeX: \displaystyle h= 8$ and $LaTeX: \displaystyle k = -14$ . The vertex is located at $LaTeX: \displaystyle (8,-14)$ and the vertex form is $LaTeX: \displaystyle f(x) = a(x-h)^2+k=\left(x - 8\right)^{2} - 14$ .