Use the discriminant, $LaTeX: \displaystyle b^2-4ac$ to determine the number and type of solutions to the equation $LaTeX: \displaystyle - 8 x^{2} - 6 x + 8 = 0$ . No points will be given if the discriminant is not used.

Since the discriminant is $LaTeX: \displaystyle b^2-4ac=(-6)^2-4(-8)(8)=292$ and is positive, the equation has two real solutions.