Find the differential, $LaTeX: \displaystyle dy$ , of $LaTeX: \displaystyle y = \ln{\left(e^{2 x} + 5 \right)}$ .

The differential is given by $LaTeX: \displaystyle dy = f'(x)dx$ . Using the formula gives: $LaTeX: dy = \frac{2 e^{2 x}}{e^{2 x} + 5}\,dx$