Find the distance between the points $LaTeX: \displaystyle \left( 48, \ -60\right)$ and $LaTeX: \displaystyle \left( 160, \ 6\right)$ .

The distace formula gives $LaTeX: \displaystyle d=\sqrt{ ((160)-(48))^2 + ((6)-(-60))^2 }=\sqrt{ 12544 + 4356 }$ . Simplifying gives $LaTeX: \displaystyle d = 130$ .