Evaluate the limit LaTeX: \displaystyle \lim_{x \to -\infty}\frac{- 6 x^{2} - 7 x + 9}{- 2 x^{2} - 7 x - 1}

The limit is an indeterminate form of the type LaTeX: \displaystyle \frac{\infty}{\infty} . Using L'Hospitial's rule 2 times gives: LaTeX: \lim_{x \to -\infty}\frac{- 6 x^{2} - 7 x + 9}{- 2 x^{2} - 7 x - 1} = \lim_{x \to -\infty}\frac{- 12 x - 7}{- 4 x - 7} = \lim_{x \to -\infty}\frac{-12}{-4} = 3