$11400 is invested in two different accounts. One account pays 14% simple interest per year and the other account pays 11% simple interest per year. If the total interest earn in one year is $1326.00, how much is invested at each rate?

Let $LaTeX: \displaystyle x$ be the amount invested at 14%. Then $LaTeX: \displaystyle 11400-x$ is amount invested at 11%. This gives the equation $LaTeX: \displaystyle 0.14 x+0.11(11400 - x)=1326$ . Solving for $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x = 2400$ . So the amount in the other account is $9000.