Find the local maximum and minimum of $LaTeX: \displaystyle f(x) = 3 x^{3} - 12 x^{2} - 9 x + 2$ .

To find the critical numbers solve $LaTeX: \displaystyle f'(x) = 0$ . The derivative is $LaTeX: \displaystyle f'(x) = 9 x^{2} - 24 x - 9$ . Solving $LaTeX: \displaystyle 9 x^{2} - 24 x - 9 = 0$ gives $LaTeX: \displaystyle x = \left[ - \frac{1}{3}, \ 3\right]$ . Using the 2nd derivative test gives:
$LaTeX: \displaystyle f''\left( - \frac{1}{3} \right) = -30$ which is less than zero, so the function is concave down and $LaTeX: \displaystyle f\left(- \frac{1}{3}\right) = \frac{32}{9}$ is a local maximum.
$LaTeX: \displaystyle f''\left( 3 \right) = 30$ which is greater than zero, so the function is concave up and $LaTeX: \displaystyle f\left(3\right) = -52$ is a local minimum.