Solve the equation $LaTeX: \displaystyle \log_{5}(x + 611)-\log_{5}(x + 11)=2$ .

Using the quotient property of logarithms gives $LaTeX: \displaystyle \log_{5}\frac{x + 611}{x + 11} = 2$ . Making both sides of the equation exponents on the base $LaTeX: \displaystyle 5$ gives $LaTeX: \displaystyle \frac{x + 611}{x + 11}=25$ . Clearing the fractions by multiplying by the LCD gives $LaTeX: \displaystyle x + 611=25 x + 275$ . Isolating $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x = 14$ .