Find the local maximum and minimum of $LaTeX: \displaystyle f(x) = 7 x^{3} + 9 x^{2} - 3 x - 4$ .

To find the critical numbers solve $LaTeX: \displaystyle f'(x) = 0$ . The derivative is $LaTeX: \displaystyle f'(x) = 21 x^{2} + 18 x - 3$ . Solving $LaTeX: \displaystyle 21 x^{2} + 18 x - 3 = 0$ gives $LaTeX: \displaystyle x = \left[ -1, \ \frac{1}{7}\right]$ . Using the 2nd derivative test gives:
$LaTeX: \displaystyle f''\left( -1 \right) = -24$ which is less than zero, so the function is concave down and $LaTeX: \displaystyle f\left(-1\right) = 1$ is a local maximum.
$LaTeX: \displaystyle f''\left( \frac{1}{7} \right) = 24$ which is greater than zero, so the function is concave up and $LaTeX: \displaystyle f\left(\frac{1}{7}\right) = - \frac{207}{49}$ is a local minimum.