Solve. $LaTeX: \displaystyle \sqrt{x + 28}=\sqrt{x - 6} + 3$

Squaring both sides gives $LaTeX: \displaystyle x + 28=x + 6 \sqrt{x - 6} + 3$ . Isolating the radical gives $LaTeX: \displaystyle \frac{25}{6}=\sqrt{x - 6}$ Squaring again gives $LaTeX: \displaystyle \frac{625}{36}=x - 6$ . Solving for $LaTeX: \displaystyle x$ gives $LaTeX: \displaystyle x=\frac{841}{36}$ . Checking the solution, $LaTeX: \displaystyle x = \frac{841}{36}$ , in the original equation gives $LaTeX: \displaystyle \frac{43}{6} = \frac{43}{6}$ which is true so the solution checks.