Use Simpson's rule to find the arclength of the curve $LaTeX: \displaystyle f(x)=\sqrt{x}$ on $LaTeX: \displaystyle (1,10)$ with $LaTeX: \displaystyle n=28$ .

$LaTeX: \displaystyle \Delta x = \frac{ 10 - 1 }{ 28 }$ . $LaTeX: \displaystyle x_i = a +i\Delta x = 1 + i \frac{9}{28}$ Using the 1,4,2,...,2,4,1 pattern the sum can be written as $LaTeX: \displaystyle x_i$ can be written split into the even and odd terms. $LaTeX: \displaystyle x_k = 1 + (2k-1)\cdot \frac{9}{28}$ for $LaTeX: \displaystyle k=1$ to $LaTeX: \displaystyle k =14$ and $LaTeX: \displaystyle x_j = 1 + (2j)\cdot \frac{9}{28}$ for $LaTeX: \displaystyle j=1$ to $LaTeX: \displaystyle j =13$ . $LaTeX: \displaystyle f(1) +f(10)+4\sum_{k=1}^{14}f\left(\frac{9 k}{14} + \frac{19}{28}\right) + 2\sum_{j=1}^{13}f\left(\frac{9 j}{14} + 1\right)$ . The value is $LaTeX: \displaystyle 9.2813$