Solve $LaTeX: \displaystyle x^{2} - 122\geq 5 x + 4$

Getting zero on the right hand side and factoring gives $LaTeX: \displaystyle x^{2} - 5 x - 126=0\iff \left(x - 14\right) \left(x + 9\right)=0$ . This gives the critical numbers as $LaTeX: \displaystyle x=14$ and $LaTeX: \displaystyle x=-9$ .

Checking the sign in each region gives the solution $LaTeX: \displaystyle (-\infty, -9 ] \cup [ 14 ,\infty)$ .