Solve $LaTeX: \displaystyle 3 x^{2} - 18 x - 48=0$

Since the GCF is $LaTeX: \displaystyle 3$ we need we factor out the GCF to get $LaTeX: \displaystyle 3(x^{2} - 6 x - 16)$ . This is now a pq method factoring. The factors of $LaTeX: \displaystyle -16$ that add up to $LaTeX: \displaystyle -6$ are $LaTeX: \displaystyle 2$ and $LaTeX: \displaystyle -8$ . This gives $LaTeX: \displaystyle 3(x + 2)(x - 8)=0$ . The solutions are $LaTeX: \displaystyle x = -2$ and $LaTeX: \displaystyle x = 8$