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Questions: Algebra BusinessCalculus
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Find the limit, if it exists \(\displaystyle \lim_{x \to 4 }\frac{ \frac{5}{x^{2}} - \frac{5}{16} }{ x - 4 }\)
Building the fraction by multiplying by the LCD in the numerator and denominator gives: \begin{equation*} \frac{ \frac{5}{x^{2}} - \frac{5}{16} }{ x - 4 }\left(\frac{ 16 x^{2} }{ 16 x^{2} } \right)=\frac{ 80 - 5 x^{2} }{ 16 x^{2} \left(x - 4\right) } = \frac{ - 5 \left(x - 4\right) \left(x + 4\right) }{ 16 x^{2} \left(x - 4\right) } = - \frac{5 \left(x + 4\right)}{16 x^{2}}\end{equation*}The reduced function is continuous at \(\displaystyle x = 4\) and by the evaluation theorem \(\displaystyle \lim_{x \to 4 }- \frac{5 \left(x + 4\right)}{16 x^{2}} = - \frac{5}{32}\)
\begin{question}Find the limit, if it exists $\lim_{x \to 4 }\frac{ \frac{5}{x^{2}} - \frac{5}{16} }{ x - 4 }$ \soln{9cm}{Building the fraction by multiplying by the LCD in the numerator and denominator gives: \begin{equation*} \frac{ \frac{5}{x^{2}} - \frac{5}{16} }{ x - 4 }\left(\frac{ 16 x^{2} }{ 16 x^{2} } \right)=\frac{ 80 - 5 x^{2} }{ 16 x^{2} \left(x - 4\right) } = \frac{ - 5 \left(x - 4\right) \left(x + 4\right) }{ 16 x^{2} \left(x - 4\right) } = - \frac{5 \left(x + 4\right)}{16 x^{2}}\end{equation*}The reduced function is continuous at $x = 4$ and by the evaluation theorem $\lim_{x \to 4 }- \frac{5 \left(x + 4\right)}{16 x^{2}} = - \frac{5}{32}$} \end{question}
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<p> <p>Find the limit, if it exists <img class="equation_image" title=" \displaystyle \lim_{x \to 4 }\frac{ \frac{5}{x^{2}} - \frac{5}{16} }{ x - 4 } " src="/equation_images/%20%5Cdisplaystyle%20%5Clim_%7Bx%20%5Cto%204%20%7D%5Cfrac%7B%20%5Cfrac%7B5%7D%7Bx%5E%7B2%7D%7D%20-%20%5Cfrac%7B5%7D%7B16%7D%20%7D%7B%20x%20-%204%20%7D%20" alt="LaTeX: \displaystyle \lim_{x \to 4 }\frac{ \frac{5}{x^{2}} - \frac{5}{16} }{ x - 4 } " data-equation-content=" \displaystyle \lim_{x \to 4 }\frac{ \frac{5}{x^{2}} - \frac{5}{16} }{ x - 4 } " /> </p> </p>
<p> <p>Building the fraction by multiplying by the LCD in the numerator and denominator gives: <img class="equation_image" title=" \frac{ \frac{5}{x^{2}} - \frac{5}{16} }{ x - 4 }\left(\frac{ 16 x^{2} }{ 16 x^{2} } \right)=\frac{ 80 - 5 x^{2} }{ 16 x^{2} \left(x - 4\right) } = \frac{ - 5 \left(x - 4\right) \left(x + 4\right) }{ 16 x^{2} \left(x - 4\right) } = - \frac{5 \left(x + 4\right)}{16 x^{2}} " src="/equation_images/%20%20%5Cfrac%7B%20%5Cfrac%7B5%7D%7Bx%5E%7B2%7D%7D%20-%20%5Cfrac%7B5%7D%7B16%7D%20%7D%7B%20x%20-%204%20%7D%5Cleft%28%5Cfrac%7B%2016%20x%5E%7B2%7D%20%7D%7B%2016%20x%5E%7B2%7D%20%7D%20%5Cright%29%3D%5Cfrac%7B%2080%20-%205%20x%5E%7B2%7D%20%7D%7B%2016%20x%5E%7B2%7D%20%5Cleft%28x%20-%204%5Cright%29%20%7D%20%3D%20%5Cfrac%7B%20-%205%20%5Cleft%28x%20-%204%5Cright%29%20%5Cleft%28x%20%2B%204%5Cright%29%20%7D%7B%2016%20x%5E%7B2%7D%20%5Cleft%28x%20-%204%5Cright%29%20%7D%20%3D%20-%20%5Cfrac%7B5%20%5Cleft%28x%20%2B%204%5Cright%29%7D%7B16%20x%5E%7B2%7D%7D%20" alt="LaTeX: \frac{ \frac{5}{x^{2}} - \frac{5}{16} }{ x - 4 }\left(\frac{ 16 x^{2} }{ 16 x^{2} } \right)=\frac{ 80 - 5 x^{2} }{ 16 x^{2} \left(x - 4\right) } = \frac{ - 5 \left(x - 4\right) \left(x + 4\right) }{ 16 x^{2} \left(x - 4\right) } = - \frac{5 \left(x + 4\right)}{16 x^{2}} " data-equation-content=" \frac{ \frac{5}{x^{2}} - \frac{5}{16} }{ x - 4 }\left(\frac{ 16 x^{2} }{ 16 x^{2} } \right)=\frac{ 80 - 5 x^{2} }{ 16 x^{2} \left(x - 4\right) } = \frac{ - 5 \left(x - 4\right) \left(x + 4\right) }{ 16 x^{2} \left(x - 4\right) } = - \frac{5 \left(x + 4\right)}{16 x^{2}} " /> The reduced function is continuous at <img class="equation_image" title=" \displaystyle x = 4 " src="/equation_images/%20%5Cdisplaystyle%20x%20%3D%204%20" alt="LaTeX: \displaystyle x = 4 " data-equation-content=" \displaystyle x = 4 " /> and by the evaluation theorem <img class="equation_image" title=" \displaystyle \lim_{x \to 4 }- \frac{5 \left(x + 4\right)}{16 x^{2}} = - \frac{5}{32} " src="/equation_images/%20%5Cdisplaystyle%20%5Clim_%7Bx%20%5Cto%204%20%7D-%20%5Cfrac%7B5%20%5Cleft%28x%20%2B%204%5Cright%29%7D%7B16%20x%5E%7B2%7D%7D%20%3D%20-%20%5Cfrac%7B5%7D%7B32%7D%20" alt="LaTeX: \displaystyle \lim_{x \to 4 }- \frac{5 \left(x + 4\right)}{16 x^{2}} = - \frac{5}{32} " data-equation-content=" \displaystyle \lim_{x \to 4 }- \frac{5 \left(x + 4\right)}{16 x^{2}} = - \frac{5}{32} " /> </p> </p>