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Use the limit definition of the derivative to find \(\displaystyle f'(x)\) if \(\displaystyle f(x)= \sqrt{5 x + 6}\).
Using the difference quotient \(\displaystyle \lim_{h \to 0}\frac{f(x+h)-f(x)}{h}\) gives \(\displaystyle \lim_{h\to 0}\frac{\sqrt{5 h + 5 x + 6}-\sqrt{5 x + 6}}{h}\) Building the fraction using the conjugate gives: \(\displaystyle \frac{- \sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}}{h}\cdot\left( \frac{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}}{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}} \right)\), expanding and collecting like terms gives \(\displaystyle \lim_{h \to 0}\frac{5 h}{h \left(\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}\right)}\) Factoring out \(\displaystyle h\) and reducing gives \(\displaystyle \lim_{h\to 0}\frac{1}{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}}\). Evaluating the limit gives \(\displaystyle f'(x)=\frac{5}{2 \sqrt{5 x + 6}}\)
\begin{question}Use the limit definition of the derivative to find $f'(x)$ if $f(x)= \sqrt{5 x + 6}$. \soln{9cm}{Using the difference quotient $\lim_{h \to 0}\frac{f(x+h)-f(x)}{h}$ gives $\lim_{h\to 0}\frac{\sqrt{5 h + 5 x + 6}-\sqrt{5 x + 6}}{h}$ Building the fraction using the conjugate gives: $\frac{- \sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}}{h}\cdot\left( \frac{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}}{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}} \right)$, expanding and collecting like terms gives $\lim_{h \to 0}\frac{5 h}{h \left(\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}\right)}$ Factoring out $h$ and reducing gives $\lim_{h\to 0}\frac{1}{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}}$. Evaluating the limit gives $f'(x)=\frac{5}{2 \sqrt{5 x + 6}}$} \end{question}
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<p> <p>Use the limit definition of the derivative to find <img class="equation_image" title=" \displaystyle f'(x) " src="/equation_images/%20%5Cdisplaystyle%20f%27%28x%29%20" alt="LaTeX: \displaystyle f'(x) " data-equation-content=" \displaystyle f'(x) " /> if <img class="equation_image" title=" \displaystyle f(x)= \sqrt{5 x + 6} " src="/equation_images/%20%5Cdisplaystyle%20f%28x%29%3D%20%5Csqrt%7B5%20x%20%2B%206%7D%20" alt="LaTeX: \displaystyle f(x)= \sqrt{5 x + 6} " data-equation-content=" \displaystyle f(x)= \sqrt{5 x + 6} " /> . </p> </p>
<p> <p>Using the difference quotient <img class="equation_image" title=" \displaystyle \lim_{h \to 0}\frac{f(x+h)-f(x)}{h} " src="/equation_images/%20%5Cdisplaystyle%20%5Clim_%7Bh%20%5Cto%200%7D%5Cfrac%7Bf%28x%2Bh%29-f%28x%29%7D%7Bh%7D%20" alt="LaTeX: \displaystyle \lim_{h \to 0}\frac{f(x+h)-f(x)}{h} " data-equation-content=" \displaystyle \lim_{h \to 0}\frac{f(x+h)-f(x)}{h} " /> gives <img class="equation_image" title=" \displaystyle \lim_{h\to 0}\frac{\sqrt{5 h + 5 x + 6}-\sqrt{5 x + 6}}{h} " src="/equation_images/%20%5Cdisplaystyle%20%5Clim_%7Bh%5Cto%200%7D%5Cfrac%7B%5Csqrt%7B5%20h%20%2B%205%20x%20%2B%206%7D-%5Csqrt%7B5%20x%20%2B%206%7D%7D%7Bh%7D%20" alt="LaTeX: \displaystyle \lim_{h\to 0}\frac{\sqrt{5 h + 5 x + 6}-\sqrt{5 x + 6}}{h} " data-equation-content=" \displaystyle \lim_{h\to 0}\frac{\sqrt{5 h + 5 x + 6}-\sqrt{5 x + 6}}{h} " /> Building the fraction using the conjugate gives: <img class="equation_image" title=" \displaystyle \frac{- \sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}}{h}\cdot\left( \frac{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}}{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}} \right) " src="/equation_images/%20%5Cdisplaystyle%20%5Cfrac%7B-%20%5Csqrt%7B5%20x%20%2B%206%7D%20%2B%20%5Csqrt%7B5%20h%20%2B%205%20x%20%2B%206%7D%7D%7Bh%7D%5Ccdot%5Cleft%28%20%5Cfrac%7B%5Csqrt%7B5%20x%20%2B%206%7D%20%2B%20%5Csqrt%7B5%20h%20%2B%205%20x%20%2B%206%7D%7D%7B%5Csqrt%7B5%20x%20%2B%206%7D%20%2B%20%5Csqrt%7B5%20h%20%2B%205%20x%20%2B%206%7D%7D%20%5Cright%29%20" alt="LaTeX: \displaystyle \frac{- \sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}}{h}\cdot\left( \frac{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}}{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}} \right) " data-equation-content=" \displaystyle \frac{- \sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}}{h}\cdot\left( \frac{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}}{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}} \right) " /> , expanding and collecting like terms gives <img class="equation_image" title=" \displaystyle \lim_{h \to 0}\frac{5 h}{h \left(\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}\right)} " src="/equation_images/%20%5Cdisplaystyle%20%5Clim_%7Bh%20%5Cto%200%7D%5Cfrac%7B5%20h%7D%7Bh%20%5Cleft%28%5Csqrt%7B5%20x%20%2B%206%7D%20%2B%20%5Csqrt%7B5%20h%20%2B%205%20x%20%2B%206%7D%5Cright%29%7D%20" alt="LaTeX: \displaystyle \lim_{h \to 0}\frac{5 h}{h \left(\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}\right)} " data-equation-content=" \displaystyle \lim_{h \to 0}\frac{5 h}{h \left(\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}\right)} " /> Factoring out <img class="equation_image" title=" \displaystyle h " src="/equation_images/%20%5Cdisplaystyle%20h%20" alt="LaTeX: \displaystyle h " data-equation-content=" \displaystyle h " /> and reducing gives <img class="equation_image" title=" \displaystyle \lim_{h\to 0}\frac{1}{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}} " src="/equation_images/%20%5Cdisplaystyle%20%5Clim_%7Bh%5Cto%200%7D%5Cfrac%7B1%7D%7B%5Csqrt%7B5%20x%20%2B%206%7D%20%2B%20%5Csqrt%7B5%20h%20%2B%205%20x%20%2B%206%7D%7D%20" alt="LaTeX: \displaystyle \lim_{h\to 0}\frac{1}{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}} " data-equation-content=" \displaystyle \lim_{h\to 0}\frac{1}{\sqrt{5 x + 6} + \sqrt{5 h + 5 x + 6}} " /> . Evaluating the limit gives <img class="equation_image" title=" \displaystyle f'(x)=\frac{5}{2 \sqrt{5 x + 6}} " src="/equation_images/%20%5Cdisplaystyle%20f%27%28x%29%3D%5Cfrac%7B5%7D%7B2%20%5Csqrt%7B5%20x%20%2B%206%7D%7D%20" alt="LaTeX: \displaystyle f'(x)=\frac{5}{2 \sqrt{5 x + 6}} " data-equation-content=" \displaystyle f'(x)=\frac{5}{2 \sqrt{5 x + 6}} " /> </p> </p>