\(\text{www.the}\beta\text{etafunction.com}\)
Home
Login
Questions: Algebra BusinessCalculus
Please login to create an exam or a quiz.
Evaluate the limit \(\displaystyle \lim_{x \to 9}\frac{2 x^{2} - 2 x - 144}{5 x^{2} - 49 x + 36}\)
The limit is an indeterminate form of the type \(\displaystyle \frac{0}{0}\). Using L'Hospitial's rule and then the evaluation theorem gives: \begin{equation*} \lim_{x \to 9}\frac{2 x^{2} - 2 x - 144}{5 x^{2} - 49 x + 36} = \lim_{x \to 9}\frac{4 x - 2}{10 x - 49} = \frac{4 (9) - 2}{10 (9) - 49} = \frac{34}{41} \end{equation*}
\begin{question}Evaluate the limit $\lim_{x \to 9}\frac{2 x^{2} - 2 x - 144}{5 x^{2} - 49 x + 36}$
\soln{9cm}{The limit is an indeterminate form of the type $\frac{0}{0}$. Using L'Hospitial's rule and then the evaluation theorem gives: \begin{equation*} \lim_{x \to 9}\frac{2 x^{2} - 2 x - 144}{5 x^{2} - 49 x + 36} = \lim_{x \to 9}\frac{4 x - 2}{10 x - 49} = \frac{4 (9) - 2}{10 (9) - 49} = \frac{34}{41} \end{equation*}}
\end{question}
\documentclass{article}
\usepackage{tikz}
\usepackage{amsmath}
\usepackage[margin=2cm]{geometry}
\usepackage{tcolorbox}
\newcounter{ExamNumber}
\newcounter{questioncount}
\stepcounter{questioncount}
\newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}}
\renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}}
\newif\ifShowSolution
\newcommand{\soln}[2]{%
\ifShowSolution%
\noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else%
\vspace{#1}%
\fi%
}%
\newcommand{\hideifShowSolution}[1]{%
\ifShowSolution%
%
\else%
#1%
\fi%
}%
\everymath{\displaystyle}
\ShowSolutiontrue
\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>Evaluate the limit <img class="equation_image" title=" \displaystyle \lim_{x \to 9}\frac{2 x^{2} - 2 x - 144}{5 x^{2} - 49 x + 36} " src="/equation_images/%20%5Cdisplaystyle%20%5Clim_%7Bx%20%5Cto%209%7D%5Cfrac%7B2%20x%5E%7B2%7D%20-%202%20x%20-%20144%7D%7B5%20x%5E%7B2%7D%20-%2049%20x%20%2B%2036%7D%20" alt="LaTeX: \displaystyle \lim_{x \to 9}\frac{2 x^{2} - 2 x - 144}{5 x^{2} - 49 x + 36} " data-equation-content=" \displaystyle \lim_{x \to 9}\frac{2 x^{2} - 2 x - 144}{5 x^{2} - 49 x + 36} " /> </p> </p><p> <p>The limit is an indeterminate form of the type <img class="equation_image" title=" \displaystyle \frac{0}{0} " src="/equation_images/%20%5Cdisplaystyle%20%5Cfrac%7B0%7D%7B0%7D%20" alt="LaTeX: \displaystyle \frac{0}{0} " data-equation-content=" \displaystyle \frac{0}{0} " /> . Using L'Hospitial's rule and then the evaluation theorem gives: <img class="equation_image" title=" \lim_{x \to 9}\frac{2 x^{2} - 2 x - 144}{5 x^{2} - 49 x + 36} = \lim_{x \to 9}\frac{4 x - 2}{10 x - 49} = \frac{4 (9) - 2}{10 (9) - 49} = \frac{34}{41} " src="/equation_images/%20%20%5Clim_%7Bx%20%5Cto%209%7D%5Cfrac%7B2%20x%5E%7B2%7D%20-%202%20x%20-%20144%7D%7B5%20x%5E%7B2%7D%20-%2049%20x%20%2B%2036%7D%20%3D%20%5Clim_%7Bx%20%5Cto%209%7D%5Cfrac%7B4%20x%20-%202%7D%7B10%20x%20-%2049%7D%20%3D%20%5Cfrac%7B4%20%289%29%20-%202%7D%7B10%20%289%29%20-%2049%7D%20%3D%20%5Cfrac%7B34%7D%7B41%7D%20%20" alt="LaTeX: \lim_{x \to 9}\frac{2 x^{2} - 2 x - 144}{5 x^{2} - 49 x + 36} = \lim_{x \to 9}\frac{4 x - 2}{10 x - 49} = \frac{4 (9) - 2}{10 (9) - 49} = \frac{34}{41} " data-equation-content=" \lim_{x \to 9}\frac{2 x^{2} - 2 x - 144}{5 x^{2} - 49 x + 36} = \lim_{x \to 9}\frac{4 x - 2}{10 x - 49} = \frac{4 (9) - 2}{10 (9) - 49} = \frac{34}{41} " /> </p> </p>