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Use \(\displaystyle \int\limits_{-9}^{0} f{\left(x \right)}\, dx=6\) and \(\displaystyle \int\limits_{0}^{5} f{\left(x \right)}\, dx=8\) to find the value of \(\displaystyle \int\limits_{-9}^{5} f{\left(x \right)}\, dx\).
Using the property \(\displaystyle \int_{a}^{b}f(x)\,dx = \int_{a}^{c}f(x)\,dx + \int_{c}^{b}f(x)\,dx\) gives:
\(\displaystyle \int\limits_{-9}^{5} f{\left(x \right)}\, dx = \int\limits_{-9}^{0} f{\left(x \right)}\, dx + \int\limits_{0}^{5} f{\left(x \right)}\, dx = 6+8=14\)
\begin{question}Use $\int\limits_{-9}^{0} f{\left(x \right)}\, dx=6$ and $\int\limits_{0}^{5} f{\left(x \right)}\, dx=8$ to find the value of $\int\limits_{-9}^{5} f{\left(x \right)}\, dx$. \soln{9cm}{Using the property $\int_{a}^{b}f(x)\,dx = \int_{a}^{c}f(x)\,dx + \int_{c}^{b}f(x)\,dx$ gives:\newline $\int\limits_{-9}^{5} f{\left(x \right)}\, dx = \int\limits_{-9}^{0} f{\left(x \right)}\, dx + \int\limits_{0}^{5} f{\left(x \right)}\, dx = 6+8=14$} \end{question}
\documentclass{article} \usepackage{tikz} \usepackage{amsmath} \usepackage[margin=2cm]{geometry} \usepackage{tcolorbox} \newcounter{ExamNumber} \newcounter{questioncount} \stepcounter{questioncount} \newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}} \renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}} \newif\ifShowSolution \newcommand{\soln}[2]{% \ifShowSolution% \noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else% \vspace{#1}% \fi% }% \newcommand{\hideifShowSolution}[1]{% \ifShowSolution% % \else% #1% \fi% }% \everymath{\displaystyle} \ShowSolutiontrue \begin{document}\begin{question}(10pts) The question goes here! \soln{9cm}{The solution goes here.} \end{question}\end{document}
<p> <p>Use <img class="equation_image" title=" \displaystyle \int\limits_{-9}^{0} f{\left(x \right)}\, dx=6 " src="/equation_images/%20%5Cdisplaystyle%20%5Cint%5Climits_%7B-9%7D%5E%7B0%7D%20f%7B%5Cleft%28x%20%5Cright%29%7D%5C%2C%20dx%3D6%20" alt="LaTeX: \displaystyle \int\limits_{-9}^{0} f{\left(x \right)}\, dx=6 " data-equation-content=" \displaystyle \int\limits_{-9}^{0} f{\left(x \right)}\, dx=6 " /> and <img class="equation_image" title=" \displaystyle \int\limits_{0}^{5} f{\left(x \right)}\, dx=8 " src="/equation_images/%20%5Cdisplaystyle%20%5Cint%5Climits_%7B0%7D%5E%7B5%7D%20f%7B%5Cleft%28x%20%5Cright%29%7D%5C%2C%20dx%3D8%20" alt="LaTeX: \displaystyle \int\limits_{0}^{5} f{\left(x \right)}\, dx=8 " data-equation-content=" \displaystyle \int\limits_{0}^{5} f{\left(x \right)}\, dx=8 " /> to find the value of <img class="equation_image" title=" \displaystyle \int\limits_{-9}^{5} f{\left(x \right)}\, dx " src="/equation_images/%20%5Cdisplaystyle%20%5Cint%5Climits_%7B-9%7D%5E%7B5%7D%20f%7B%5Cleft%28x%20%5Cright%29%7D%5C%2C%20dx%20" alt="LaTeX: \displaystyle \int\limits_{-9}^{5} f{\left(x \right)}\, dx " data-equation-content=" \displaystyle \int\limits_{-9}^{5} f{\left(x \right)}\, dx " /> . </p> </p>
<p> <p>Using the property <img class="equation_image" title=" \displaystyle \int_{a}^{b}f(x)\,dx = \int_{a}^{c}f(x)\,dx + \int_{c}^{b}f(x)\,dx " src="/equation_images/%20%5Cdisplaystyle%20%5Cint_%7Ba%7D%5E%7Bb%7Df%28x%29%5C%2Cdx%20%3D%20%5Cint_%7Ba%7D%5E%7Bc%7Df%28x%29%5C%2Cdx%20%2B%20%5Cint_%7Bc%7D%5E%7Bb%7Df%28x%29%5C%2Cdx%20" alt="LaTeX: \displaystyle \int_{a}^{b}f(x)\,dx = \int_{a}^{c}f(x)\,dx + \int_{c}^{b}f(x)\,dx " data-equation-content=" \displaystyle \int_{a}^{b}f(x)\,dx = \int_{a}^{c}f(x)\,dx + \int_{c}^{b}f(x)\,dx " /> gives:<br>
<img class="equation_image" title=" \displaystyle \int\limits_{-9}^{5} f{\left(x \right)}\, dx = \int\limits_{-9}^{0} f{\left(x \right)}\, dx + \int\limits_{0}^{5} f{\left(x \right)}\, dx = 6+8=14 " src="/equation_images/%20%5Cdisplaystyle%20%5Cint%5Climits_%7B-9%7D%5E%7B5%7D%20f%7B%5Cleft%28x%20%5Cright%29%7D%5C%2C%20dx%20%3D%20%5Cint%5Climits_%7B-9%7D%5E%7B0%7D%20f%7B%5Cleft%28x%20%5Cright%29%7D%5C%2C%20dx%20%2B%20%5Cint%5Climits_%7B0%7D%5E%7B5%7D%20f%7B%5Cleft%28x%20%5Cright%29%7D%5C%2C%20dx%20%3D%206%2B8%3D14%20" alt="LaTeX: \displaystyle \int\limits_{-9}^{5} f{\left(x \right)}\, dx = \int\limits_{-9}^{0} f{\left(x \right)}\, dx + \int\limits_{0}^{5} f{\left(x \right)}\, dx = 6+8=14 " data-equation-content=" \displaystyle \int\limits_{-9}^{5} f{\left(x \right)}\, dx = \int\limits_{-9}^{0} f{\left(x \right)}\, dx + \int\limits_{0}^{5} f{\left(x \right)}\, dx = 6+8=14 " /> </p> </p>