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Use 6 rectangles to approximate \(\displaystyle \int\limits_{1}^{5} \ln{\left(x \right)}\, dx\) using the left endpoint. Draw a graph showing the sum.


\(\displaystyle \Delta x = \frac{b-a}{n}=\frac{2}{3}\) and \(\displaystyle x_i = a+i\Delta x = \frac{2 i}{3} + 1\). Drawing a graph gives:

The sum is \(\displaystyle \sum_{i=0}^{5} \frac{2 \ln{\left(\frac{2 i}{3} + 1 \right)}}{3} = 3.4816\).

Download Tikz \( \LaTeX \)

\begin{tikzpicture}[yscale=2]
	\draw[very thick, color=blue, opacity=0.3, xstep=1, ystep=1] (-1,-1) grid (6,2.10000000000000);
	\draw[latex-latex, very thick] (-1.4,0)--(6.4,0) node[right]{$x$};
	\draw[latex-latex, very thick] (0,-1.1)--(0,2.2) node[above]{$y$};
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		\draw[thick](3.00, 1.10) rectangle (3.67, 0);
		\draw[fill=blue, opacity=0.3](3.67, 1.30) rectangle (4.33, 0);
		\draw[thick](3.67, 1.30) rectangle (4.33, 0);
		\draw[fill=blue, opacity=0.3](4.33, 1.47) rectangle (5.00, 0);
		\draw[thick](4.33, 1.47) rectangle (5.00, 0);
\end{tikzpicture}

Download \(\LaTeX\)

\begin{question}Use 6 rectangles to approximate $\int\limits_{1}^{5} \ln{\left(x \right)}\, dx$ using the left endpoint. Draw a graph showing the sum. 
    \soln{9cm}{$\Delta x = \frac{b-a}{n}=\frac{2}{3}$ and $x_i = a+i\Delta x = \frac{2 i}{3} + 1$. Drawing a graph gives:
\begin{center}\begin{tikzpicture}[yscale=2]
	\draw[very thick, color=blue, opacity=0.3, xstep=1, ystep=1] (-1,-1) grid (6,2.10000000000000);
	\draw[latex-latex, very thick] (-1.4,0)--(6.4,0) node[right]{$x$};
	\draw[latex-latex, very thick] (0,-1.1)--(0,2.2) node[above]{$y$};
	\foreach \x in { -1,1,...,6 }{
		\pgfmathsetmacro{\xtick}{\x != 0 ? "\x" : ""}
		\draw (\x, .2) -- (\x,-.2) node[below]{$\xtick$};
		}
	\foreach \y in { -1,-0.5,...,2.10000000000000 }{
		\pgfmathsetmacro{\ytick}{\y != 0 ? "\y" : ""}
		\draw (.2, \y) -- (-.2, \y) node[left]{$\ytick$};
		}
	\draw[thick, color=blue, domain={1.0}:{5.0}, samples=200, samples =350] plot(\x, {ln((\x))});
		\draw[fill=blue, opacity=0.3](1.00, 0) rectangle (1.67, 0);
		\draw[thick](1.00, 0) rectangle (1.67, 0);
		\draw[fill=blue, opacity=0.3](1.67, 0.511) rectangle (2.33, 0);
		\draw[thick](1.67, 0.511) rectangle (2.33, 0);
		\draw[fill=blue, opacity=0.3](2.33, 0.847) rectangle (3.00, 0);
		\draw[thick](2.33, 0.847) rectangle (3.00, 0);
		\draw[fill=blue, opacity=0.3](3.00, 1.10) rectangle (3.67, 0);
		\draw[thick](3.00, 1.10) rectangle (3.67, 0);
		\draw[fill=blue, opacity=0.3](3.67, 1.30) rectangle (4.33, 0);
		\draw[thick](3.67, 1.30) rectangle (4.33, 0);
		\draw[fill=blue, opacity=0.3](4.33, 1.47) rectangle (5.00, 0);
		\draw[thick](4.33, 1.47) rectangle (5.00, 0);
\end{tikzpicture}

\end{center}
The sum is $\sum_{i=0}^{5} \frac{2 \ln{\left(\frac{2 i}{3} + 1 \right)}}{3} = 3.4816$. }

\end{question}

Download Question and Solution Environment\(\LaTeX\)
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\begin{document}\begin{question}(10pts) The question goes here!
    \soln{9cm}{The solution goes here.}

\end{question}\end{document}
HTML for Canvas
<p> <p>Use 6 rectangles to approximate  <img class="equation_image" title=" \displaystyle \int\limits_{1}^{5} \ln{\left(x \right)}\, dx " src="/equation_images/%20%5Cdisplaystyle%20%5Cint%5Climits_%7B1%7D%5E%7B5%7D%20%5Cln%7B%5Cleft%28x%20%5Cright%29%7D%5C%2C%20dx%20" alt="LaTeX:  \displaystyle \int\limits_{1}^{5} \ln{\left(x \right)}\, dx " data-equation-content=" \displaystyle \int\limits_{1}^{5} \ln{\left(x \right)}\, dx " />  using the left endpoint. Draw a graph showing the sum. </p> </p>
HTML for Canvas
<p> <p> <img class="equation_image" title=" \displaystyle \Delta x = \frac{b-a}{n}=\frac{2}{3} " src="/equation_images/%20%5Cdisplaystyle%20%5CDelta%20x%20%3D%20%5Cfrac%7Bb-a%7D%7Bn%7D%3D%5Cfrac%7B2%7D%7B3%7D%20" alt="LaTeX:  \displaystyle \Delta x = \frac{b-a}{n}=\frac{2}{3} " data-equation-content=" \displaystyle \Delta x = \frac{b-a}{n}=\frac{2}{3} " />  and  <img class="equation_image" title=" \displaystyle x_i = a+i\Delta x = \frac{2 i}{3} + 1 " src="/equation_images/%20%5Cdisplaystyle%20x_i%20%3D%20a%2Bi%5CDelta%20x%20%3D%20%5Cfrac%7B2%20i%7D%7B3%7D%20%2B%201%20" alt="LaTeX:  \displaystyle x_i = a+i\Delta x = \frac{2 i}{3} + 1 " data-equation-content=" \displaystyle x_i = a+i\Delta x = \frac{2 i}{3} + 1 " /> . Drawing a graph gives:
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</center>
The sum is  <img class="equation_image" title=" \displaystyle \sum_{i=0}^{5} \frac{2 \ln{\left(\frac{2 i}{3} + 1 \right)}}{3} = 3.4816 " src="/equation_images/%20%5Cdisplaystyle%20%5Csum_%7Bi%3D0%7D%5E%7B5%7D%20%5Cfrac%7B2%20%5Cln%7B%5Cleft%28%5Cfrac%7B2%20i%7D%7B3%7D%20%2B%201%20%5Cright%29%7D%7D%7B3%7D%20%3D%203.4816%20" alt="LaTeX:  \displaystyle \sum_{i=0}^{5} \frac{2 \ln{\left(\frac{2 i}{3} + 1 \right)}}{3} = 3.4816 " data-equation-content=" \displaystyle \sum_{i=0}^{5} \frac{2 \ln{\left(\frac{2 i}{3} + 1 \right)}}{3} = 3.4816 " /> . </p> </p>