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Questions: Algebra BusinessCalculus
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Find \(\displaystyle \int\limits_{6}^{12} \left(5 x^{3} + 5 x^{2} - 6 x + 8\right)\, dx\).
The indefinite integtal is \(\displaystyle F(x)=\frac{5 x^{4}}{4} + \frac{5 x^{3}}{3} - 3 x^{2} + 8 x+C\). Using the Fundamental Theorem of Calculus Part II gives \(\displaystyle F(12)-F(6)=\left(28464\right)-\left(1920\right) = 26544\).
\begin{question}Find $\int\limits_{6}^{12} \left(5 x^{3} + 5 x^{2} - 6 x + 8\right)\, dx$. \soln{9cm}{The indefinite integtal is $F(x)=\frac{5 x^{4}}{4} + \frac{5 x^{3}}{3} - 3 x^{2} + 8 x+C$. Using the Fundamental Theorem of Calculus Part II gives $F(12)-F(6)=\left(28464\right)-\left(1920\right) = 26544$. } \end{question}
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<p> <p>Find <img class="equation_image" title=" \displaystyle \int\limits_{6}^{12} \left(5 x^{3} + 5 x^{2} - 6 x + 8\right)\, dx " src="/equation_images/%20%5Cdisplaystyle%20%5Cint%5Climits_%7B6%7D%5E%7B12%7D%20%5Cleft%285%20x%5E%7B3%7D%20%2B%205%20x%5E%7B2%7D%20-%206%20x%20%2B%208%5Cright%29%5C%2C%20dx%20" alt="LaTeX: \displaystyle \int\limits_{6}^{12} \left(5 x^{3} + 5 x^{2} - 6 x + 8\right)\, dx " data-equation-content=" \displaystyle \int\limits_{6}^{12} \left(5 x^{3} + 5 x^{2} - 6 x + 8\right)\, dx " /> . </p> </p>
<p> <p>The indefinite integtal is <img class="equation_image" title=" \displaystyle F(x)=\frac{5 x^{4}}{4} + \frac{5 x^{3}}{3} - 3 x^{2} + 8 x+C " src="/equation_images/%20%5Cdisplaystyle%20F%28x%29%3D%5Cfrac%7B5%20x%5E%7B4%7D%7D%7B4%7D%20%2B%20%5Cfrac%7B5%20x%5E%7B3%7D%7D%7B3%7D%20-%203%20x%5E%7B2%7D%20%2B%208%20x%2BC%20" alt="LaTeX: \displaystyle F(x)=\frac{5 x^{4}}{4} + \frac{5 x^{3}}{3} - 3 x^{2} + 8 x+C " data-equation-content=" \displaystyle F(x)=\frac{5 x^{4}}{4} + \frac{5 x^{3}}{3} - 3 x^{2} + 8 x+C " /> . Using the Fundamental Theorem of Calculus Part II gives <img class="equation_image" title=" \displaystyle F(12)-F(6)=\left(28464\right)-\left(1920\right) = 26544 " src="/equation_images/%20%5Cdisplaystyle%20F%2812%29-F%286%29%3D%5Cleft%2828464%5Cright%29-%5Cleft%281920%5Cright%29%20%3D%2026544%20" alt="LaTeX: \displaystyle F(12)-F(6)=\left(28464\right)-\left(1920\right) = 26544 " data-equation-content=" \displaystyle F(12)-F(6)=\left(28464\right)-\left(1920\right) = 26544 " /> . </p> </p>