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Questions: Algebra BusinessCalculus
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Evaluate \(\displaystyle \int \left(- \frac{2}{x^{2}}\right)\, dx\)
Pulling the constant out of the integral gives \(\displaystyle - 2 \int \frac{1}{x^{2}}\, dx\). Taking the integral gives \(\displaystyle \frac{2}{x}+C\)
\begin{question}Evaluate $\int \left(- \frac{2}{x^{2}}\right)\, dx$ \soln{9cm}{Pulling the constant out of the integral gives $- 2 \int \frac{1}{x^{2}}\, dx$. Taking the integral gives $\frac{2}{x}+C$} \end{question}
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<p> <p>Evaluate <img class="equation_image" title=" \displaystyle \int \left(- \frac{2}{x^{2}}\right)\, dx " src="/equation_images/%20%5Cdisplaystyle%20%5Cint%20%5Cleft%28-%20%5Cfrac%7B2%7D%7Bx%5E%7B2%7D%7D%5Cright%29%5C%2C%20dx%20" alt="LaTeX: \displaystyle \int \left(- \frac{2}{x^{2}}\right)\, dx " data-equation-content=" \displaystyle \int \left(- \frac{2}{x^{2}}\right)\, dx " /> </p> </p>
<p> <p>Pulling the constant out of the integral gives <img class="equation_image" title=" \displaystyle - 2 \int \frac{1}{x^{2}}\, dx " src="/equation_images/%20%5Cdisplaystyle%20-%202%20%5Cint%20%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%7D%5C%2C%20dx%20" alt="LaTeX: \displaystyle - 2 \int \frac{1}{x^{2}}\, dx " data-equation-content=" \displaystyle - 2 \int \frac{1}{x^{2}}\, dx " /> . Taking the integral gives <img class="equation_image" title=" \displaystyle \frac{2}{x}+C " src="/equation_images/%20%5Cdisplaystyle%20%5Cfrac%7B2%7D%7Bx%7D%2BC%20" alt="LaTeX: \displaystyle \frac{2}{x}+C " data-equation-content=" \displaystyle \frac{2}{x}+C " /> </p> </p>