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Questions: Algebra BusinessCalculus
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Find the derivative of \(\displaystyle f(x) = \sin{\left(e^{4 x} \right)}\).
Decomposing the function gives \(\displaystyle f(u) = \sin{\left(u \right)}\), \(\displaystyle u = v^{4}\), and \(\displaystyle v = e^{x}.\) Using the chain rule \(\displaystyle f'(x) = \frac{df}{du}\frac{du}{dv}\frac{dv}{dx}\). \(\displaystyle f'(x) = (\cos{\left(u \right)})(4 v^{3})(e^{x}) = 4 v^{3} e^{x} \cos{\left(u \right)}\). Substituting back in \(\displaystyle u\) and \(\displaystyle v\) gives \(\displaystyle f'(x) = 4 v^{3} e^{x} \cos{\left(v^{4} \right)} = 4 e^{4 x} \cos{\left(e^{4 x} \right)}\).
\begin{question}Find the derivative of $f(x) = \sin{\left(e^{4 x} \right)}$. \soln{9cm}{Decomposing the function gives $f(u) = \sin{\left(u \right)}$, $u = v^{4}$, and $ v = e^{x}.$ Using the chain rule $f'(x) = \frac{df}{du}\frac{du}{dv}\frac{dv}{dx}$. $f'(x) = (\cos{\left(u \right)})(4 v^{3})(e^{x}) = 4 v^{3} e^{x} \cos{\left(u \right)}$. Substituting back in $u$ and $v$ gives $f'(x) = 4 v^{3} e^{x} \cos{\left(v^{4} \right)} = 4 e^{4 x} \cos{\left(e^{4 x} \right)}$. } \end{question}
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<p> <p>Find the derivative of <img class="equation_image" title=" \displaystyle f(x) = \sin{\left(e^{4 x} \right)} " src="/equation_images/%20%5Cdisplaystyle%20f%28x%29%20%3D%20%5Csin%7B%5Cleft%28e%5E%7B4%20x%7D%20%5Cright%29%7D%20" alt="LaTeX: \displaystyle f(x) = \sin{\left(e^{4 x} \right)} " data-equation-content=" \displaystyle f(x) = \sin{\left(e^{4 x} \right)} " /> . </p> </p>
<p> <p>Decomposing the function gives <img class="equation_image" title=" \displaystyle f(u) = \sin{\left(u \right)} " src="/equation_images/%20%5Cdisplaystyle%20f%28u%29%20%3D%20%5Csin%7B%5Cleft%28u%20%5Cright%29%7D%20" alt="LaTeX: \displaystyle f(u) = \sin{\left(u \right)} " data-equation-content=" \displaystyle f(u) = \sin{\left(u \right)} " /> , <img class="equation_image" title=" \displaystyle u = v^{4} " src="/equation_images/%20%5Cdisplaystyle%20u%20%3D%20v%5E%7B4%7D%20" alt="LaTeX: \displaystyle u = v^{4} " data-equation-content=" \displaystyle u = v^{4} " /> , and <img class="equation_image" title=" \displaystyle v = e^{x}. " src="/equation_images/%20%5Cdisplaystyle%20%20v%20%3D%20e%5E%7Bx%7D.%20" alt="LaTeX: \displaystyle v = e^{x}. " data-equation-content=" \displaystyle v = e^{x}. " /> Using the chain rule <img class="equation_image" title=" \displaystyle f'(x) = \frac{df}{du}\frac{du}{dv}\frac{dv}{dx} " src="/equation_images/%20%5Cdisplaystyle%20f%27%28x%29%20%3D%20%5Cfrac%7Bdf%7D%7Bdu%7D%5Cfrac%7Bdu%7D%7Bdv%7D%5Cfrac%7Bdv%7D%7Bdx%7D%20" alt="LaTeX: \displaystyle f'(x) = \frac{df}{du}\frac{du}{dv}\frac{dv}{dx} " data-equation-content=" \displaystyle f'(x) = \frac{df}{du}\frac{du}{dv}\frac{dv}{dx} " /> . <img class="equation_image" title=" \displaystyle f'(x) = (\cos{\left(u \right)})(4 v^{3})(e^{x}) = 4 v^{3} e^{x} \cos{\left(u \right)} " src="/equation_images/%20%5Cdisplaystyle%20f%27%28x%29%20%3D%20%28%5Ccos%7B%5Cleft%28u%20%5Cright%29%7D%29%284%20v%5E%7B3%7D%29%28e%5E%7Bx%7D%29%20%3D%204%20v%5E%7B3%7D%20e%5E%7Bx%7D%20%5Ccos%7B%5Cleft%28u%20%5Cright%29%7D%20" alt="LaTeX: \displaystyle f'(x) = (\cos{\left(u \right)})(4 v^{3})(e^{x}) = 4 v^{3} e^{x} \cos{\left(u \right)} " data-equation-content=" \displaystyle f'(x) = (\cos{\left(u \right)})(4 v^{3})(e^{x}) = 4 v^{3} e^{x} \cos{\left(u \right)} " /> . Substituting back in <img class="equation_image" title=" \displaystyle u " src="/equation_images/%20%5Cdisplaystyle%20u%20" alt="LaTeX: \displaystyle u " data-equation-content=" \displaystyle u " /> and <img class="equation_image" title=" \displaystyle v " src="/equation_images/%20%5Cdisplaystyle%20v%20" alt="LaTeX: \displaystyle v " data-equation-content=" \displaystyle v " /> gives <img class="equation_image" title=" \displaystyle f'(x) = 4 v^{3} e^{x} \cos{\left(v^{4} \right)} = 4 e^{4 x} \cos{\left(e^{4 x} \right)} " src="/equation_images/%20%5Cdisplaystyle%20f%27%28x%29%20%3D%204%20v%5E%7B3%7D%20e%5E%7Bx%7D%20%5Ccos%7B%5Cleft%28v%5E%7B4%7D%20%5Cright%29%7D%20%3D%204%20e%5E%7B4%20x%7D%20%5Ccos%7B%5Cleft%28e%5E%7B4%20x%7D%20%5Cright%29%7D%20" alt="LaTeX: \displaystyle f'(x) = 4 v^{3} e^{x} \cos{\left(v^{4} \right)} = 4 e^{4 x} \cos{\left(e^{4 x} \right)} " data-equation-content=" \displaystyle f'(x) = 4 v^{3} e^{x} \cos{\left(v^{4} \right)} = 4 e^{4 x} \cos{\left(e^{4 x} \right)} " /> . </p> </p>