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Questions: Algebra BusinessCalculus
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Find the derivative of \(\displaystyle y = (e^{x})(7 x^{2} - 3 x + 6)(- 8 x^{2} - 3 x + 4)\).
Identifying \(\displaystyle f=e^{x}\) and \(\displaystyle g=\left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right)\) and using the product rule with \(\displaystyle f=e^{x} \implies f'=e^{x}\). This leaves g as \(\displaystyle g = \left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right)\) which also requires the product rule. Pushing down in the new product rule \(\displaystyle f=7 x^{2} - 3 x + 6 \implies f'=14 x - 3\) and \(\displaystyle g=- 8 x^{2} - 3 x + 4 \implies g'=- 16 x - 3\). Popping up a level gives \(\displaystyle g'=(- 8 x^{2} - 3 x + 4)(14 x - 3)+(7 x^{2} - 3 x + 6)(- 16 x - 3)\)Popping up again (Back to the original problem) gives \(\displaystyle f'=(e^{x})(\left(- 16 x - 3\right) \left(7 x^{2} - 3 x + 6\right) + \left(14 x - 3\right) \left(- 8 x^{2} - 3 x + 4\right))+(\left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right))(e^{x})=\left(- 16 x - 3\right) \left(7 x^{2} - 3 x + 6\right) e^{x} + \left(14 x - 3\right) \left(- 8 x^{2} - 3 x + 4\right) e^{x} + \left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right) e^{x}\)
\begin{question}Find the derivative of $y = (e^{x})(7 x^{2} - 3 x + 6)(- 8 x^{2} - 3 x + 4)$.
\soln{9cm}{Identifying $f=e^{x}$ and $g=\left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right)$ and using the product rule with $f=e^{x} \implies f'=e^{x}$. This leaves g as $g = \left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right)$ which also requires the product rule. Pushing down in the new product rule $f=7 x^{2} - 3 x + 6 \implies f'=14 x - 3$ and $g=- 8 x^{2} - 3 x + 4 \implies g'=- 16 x - 3$. Popping up a level gives $g'=(- 8 x^{2} - 3 x + 4)(14 x - 3)+(7 x^{2} - 3 x + 6)(- 16 x - 3)$Popping up again (Back to the original problem) gives $f'=(e^{x})(\left(- 16 x - 3\right) \left(7 x^{2} - 3 x + 6\right) + \left(14 x - 3\right) \left(- 8 x^{2} - 3 x + 4\right))+(\left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right))(e^{x})=\left(- 16 x - 3\right) \left(7 x^{2} - 3 x + 6\right) e^{x} + \left(14 x - 3\right) \left(- 8 x^{2} - 3 x + 4\right) e^{x} + \left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right) e^{x}$}
\end{question}
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\begin{document}\begin{question}(10pts) The question goes here!
\soln{9cm}{The solution goes here.}
\end{question}\end{document}<p> <p>Find the derivative of <img class="equation_image" title=" \displaystyle y = (e^{x})(7 x^{2} - 3 x + 6)(- 8 x^{2} - 3 x + 4) " src="/equation_images/%20%5Cdisplaystyle%20y%20%3D%20%28e%5E%7Bx%7D%29%287%20x%5E%7B2%7D%20-%203%20x%20%2B%206%29%28-%208%20x%5E%7B2%7D%20-%203%20x%20%2B%204%29%20" alt="LaTeX: \displaystyle y = (e^{x})(7 x^{2} - 3 x + 6)(- 8 x^{2} - 3 x + 4) " data-equation-content=" \displaystyle y = (e^{x})(7 x^{2} - 3 x + 6)(- 8 x^{2} - 3 x + 4) " /> .</p> </p><p> <p>Identifying <img class="equation_image" title=" \displaystyle f=e^{x} " src="/equation_images/%20%5Cdisplaystyle%20f%3De%5E%7Bx%7D%20" alt="LaTeX: \displaystyle f=e^{x} " data-equation-content=" \displaystyle f=e^{x} " /> and <img class="equation_image" title=" \displaystyle g=\left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right) " src="/equation_images/%20%5Cdisplaystyle%20g%3D%5Cleft%28-%208%20x%5E%7B2%7D%20-%203%20x%20%2B%204%5Cright%29%20%5Cleft%287%20x%5E%7B2%7D%20-%203%20x%20%2B%206%5Cright%29%20" alt="LaTeX: \displaystyle g=\left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right) " data-equation-content=" \displaystyle g=\left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right) " /> and using the product rule with <img class="equation_image" title=" \displaystyle f=e^{x} \implies f'=e^{x} " src="/equation_images/%20%5Cdisplaystyle%20f%3De%5E%7Bx%7D%20%5Cimplies%20f%27%3De%5E%7Bx%7D%20" alt="LaTeX: \displaystyle f=e^{x} \implies f'=e^{x} " data-equation-content=" \displaystyle f=e^{x} \implies f'=e^{x} " /> . This leaves g as <img class="equation_image" title=" \displaystyle g = \left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right) " src="/equation_images/%20%5Cdisplaystyle%20g%20%3D%20%5Cleft%28-%208%20x%5E%7B2%7D%20-%203%20x%20%2B%204%5Cright%29%20%5Cleft%287%20x%5E%7B2%7D%20-%203%20x%20%2B%206%5Cright%29%20" alt="LaTeX: \displaystyle g = \left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right) " data-equation-content=" \displaystyle g = \left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right) " /> which also requires the product rule. Pushing down in the new product rule <img class="equation_image" title=" \displaystyle f=7 x^{2} - 3 x + 6 \implies f'=14 x - 3 " src="/equation_images/%20%5Cdisplaystyle%20f%3D7%20x%5E%7B2%7D%20-%203%20x%20%2B%206%20%5Cimplies%20f%27%3D14%20x%20-%203%20" alt="LaTeX: \displaystyle f=7 x^{2} - 3 x + 6 \implies f'=14 x - 3 " data-equation-content=" \displaystyle f=7 x^{2} - 3 x + 6 \implies f'=14 x - 3 " /> and <img class="equation_image" title=" \displaystyle g=- 8 x^{2} - 3 x + 4 \implies g'=- 16 x - 3 " src="/equation_images/%20%5Cdisplaystyle%20g%3D-%208%20x%5E%7B2%7D%20-%203%20x%20%2B%204%20%5Cimplies%20g%27%3D-%2016%20x%20-%203%20" alt="LaTeX: \displaystyle g=- 8 x^{2} - 3 x + 4 \implies g'=- 16 x - 3 " data-equation-content=" \displaystyle g=- 8 x^{2} - 3 x + 4 \implies g'=- 16 x - 3 " /> . Popping up a level gives <img class="equation_image" title=" \displaystyle g'=(- 8 x^{2} - 3 x + 4)(14 x - 3)+(7 x^{2} - 3 x + 6)(- 16 x - 3) " src="/equation_images/%20%5Cdisplaystyle%20g%27%3D%28-%208%20x%5E%7B2%7D%20-%203%20x%20%2B%204%29%2814%20x%20-%203%29%2B%287%20x%5E%7B2%7D%20-%203%20x%20%2B%206%29%28-%2016%20x%20-%203%29%20" alt="LaTeX: \displaystyle g'=(- 8 x^{2} - 3 x + 4)(14 x - 3)+(7 x^{2} - 3 x + 6)(- 16 x - 3) " data-equation-content=" \displaystyle g'=(- 8 x^{2} - 3 x + 4)(14 x - 3)+(7 x^{2} - 3 x + 6)(- 16 x - 3) " /> Popping up again (Back to the original problem) gives <img class="equation_image" title=" \displaystyle f'=(e^{x})(\left(- 16 x - 3\right) \left(7 x^{2} - 3 x + 6\right) + \left(14 x - 3\right) \left(- 8 x^{2} - 3 x + 4\right))+(\left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right))(e^{x})=\left(- 16 x - 3\right) \left(7 x^{2} - 3 x + 6\right) e^{x} + \left(14 x - 3\right) \left(- 8 x^{2} - 3 x + 4\right) e^{x} + \left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right) e^{x} " src="/equation_images/%20%5Cdisplaystyle%20f%27%3D%28e%5E%7Bx%7D%29%28%5Cleft%28-%2016%20x%20-%203%5Cright%29%20%5Cleft%287%20x%5E%7B2%7D%20-%203%20x%20%2B%206%5Cright%29%20%2B%20%5Cleft%2814%20x%20-%203%5Cright%29%20%5Cleft%28-%208%20x%5E%7B2%7D%20-%203%20x%20%2B%204%5Cright%29%29%2B%28%5Cleft%28-%208%20x%5E%7B2%7D%20-%203%20x%20%2B%204%5Cright%29%20%5Cleft%287%20x%5E%7B2%7D%20-%203%20x%20%2B%206%5Cright%29%29%28e%5E%7Bx%7D%29%3D%5Cleft%28-%2016%20x%20-%203%5Cright%29%20%5Cleft%287%20x%5E%7B2%7D%20-%203%20x%20%2B%206%5Cright%29%20e%5E%7Bx%7D%20%2B%20%5Cleft%2814%20x%20-%203%5Cright%29%20%5Cleft%28-%208%20x%5E%7B2%7D%20-%203%20x%20%2B%204%5Cright%29%20e%5E%7Bx%7D%20%2B%20%5Cleft%28-%208%20x%5E%7B2%7D%20-%203%20x%20%2B%204%5Cright%29%20%5Cleft%287%20x%5E%7B2%7D%20-%203%20x%20%2B%206%5Cright%29%20e%5E%7Bx%7D%20" alt="LaTeX: \displaystyle f'=(e^{x})(\left(- 16 x - 3\right) \left(7 x^{2} - 3 x + 6\right) + \left(14 x - 3\right) \left(- 8 x^{2} - 3 x + 4\right))+(\left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right))(e^{x})=\left(- 16 x - 3\right) \left(7 x^{2} - 3 x + 6\right) e^{x} + \left(14 x - 3\right) \left(- 8 x^{2} - 3 x + 4\right) e^{x} + \left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right) e^{x} " data-equation-content=" \displaystyle f'=(e^{x})(\left(- 16 x - 3\right) \left(7 x^{2} - 3 x + 6\right) + \left(14 x - 3\right) \left(- 8 x^{2} - 3 x + 4\right))+(\left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right))(e^{x})=\left(- 16 x - 3\right) \left(7 x^{2} - 3 x + 6\right) e^{x} + \left(14 x - 3\right) \left(- 8 x^{2} - 3 x + 4\right) e^{x} + \left(- 8 x^{2} - 3 x + 4\right) \left(7 x^{2} - 3 x + 6\right) e^{x} " /> </p> </p>