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Find the derivative of \(\displaystyle y = (\sin{\left(x \right)})(e^{x})(\cos{\left(x \right)})\).
Identifying \(\displaystyle f=\sin{\left(x \right)}\) and \(\displaystyle g=e^{x} \cos{\left(x \right)}\) and using the product rule with \(\displaystyle f=\sin{\left(x \right)} \implies f'=\cos{\left(x \right)}\). This leaves g as \(\displaystyle g = e^{x} \cos{\left(x \right)}\) which also requires the product rule. Pushing down in the new product rule \(\displaystyle f=e^{x} \implies f'=e^{x}\) and \(\displaystyle g=\cos{\left(x \right)} \implies g'=- \sin{\left(x \right)}\). Popping up a level gives \(\displaystyle g'=(\cos{\left(x \right)})(e^{x})+(e^{x})(- \sin{\left(x \right)})\)Popping up again (Back to the original problem) gives \(\displaystyle f'=(\sin{\left(x \right)})(- e^{x} \sin{\left(x \right)} + e^{x} \cos{\left(x \right)})+(e^{x} \cos{\left(x \right)})(\cos{\left(x \right)})=- e^{x} \sin^{2}{\left(x \right)} + e^{x} \sin{\left(x \right)} \cos{\left(x \right)} + e^{x} \cos^{2}{\left(x \right)}\)
\begin{question}Find the derivative of $y = (\sin{\left(x \right)})(e^{x})(\cos{\left(x \right)})$. \soln{9cm}{Identifying $f=\sin{\left(x \right)}$ and $g=e^{x} \cos{\left(x \right)}$ and using the product rule with $f=\sin{\left(x \right)} \implies f'=\cos{\left(x \right)}$. This leaves g as $g = e^{x} \cos{\left(x \right)}$ which also requires the product rule. Pushing down in the new product rule $f=e^{x} \implies f'=e^{x}$ and $g=\cos{\left(x \right)} \implies g'=- \sin{\left(x \right)}$. Popping up a level gives $g'=(\cos{\left(x \right)})(e^{x})+(e^{x})(- \sin{\left(x \right)})$Popping up again (Back to the original problem) gives $f'=(\sin{\left(x \right)})(- e^{x} \sin{\left(x \right)} + e^{x} \cos{\left(x \right)})+(e^{x} \cos{\left(x \right)})(\cos{\left(x \right)})=- e^{x} \sin^{2}{\left(x \right)} + e^{x} \sin{\left(x \right)} \cos{\left(x \right)} + e^{x} \cos^{2}{\left(x \right)}$} \end{question}
\documentclass{article} \usepackage{tikz} \usepackage{amsmath} \usepackage[margin=2cm]{geometry} \usepackage{tcolorbox} \newcounter{ExamNumber} \newcounter{questioncount} \stepcounter{questioncount} \newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}} \renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}} \newif\ifShowSolution \newcommand{\soln}[2]{% \ifShowSolution% \noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else% \vspace{#1}% \fi% }% \newcommand{\hideifShowSolution}[1]{% \ifShowSolution% % \else% #1% \fi% }% \everymath{\displaystyle} \ShowSolutiontrue \begin{document}\begin{question}(10pts) The question goes here! \soln{9cm}{The solution goes here.} \end{question}\end{document}
<p> <p>Find the derivative of <img class="equation_image" title=" \displaystyle y = (\sin{\left(x \right)})(e^{x})(\cos{\left(x \right)}) " src="/equation_images/%20%5Cdisplaystyle%20y%20%3D%20%28%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%29%28e%5E%7Bx%7D%29%28%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%29%20" alt="LaTeX: \displaystyle y = (\sin{\left(x \right)})(e^{x})(\cos{\left(x \right)}) " data-equation-content=" \displaystyle y = (\sin{\left(x \right)})(e^{x})(\cos{\left(x \right)}) " /> .</p> </p>
<p> <p>Identifying <img class="equation_image" title=" \displaystyle f=\sin{\left(x \right)} " src="/equation_images/%20%5Cdisplaystyle%20f%3D%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20" alt="LaTeX: \displaystyle f=\sin{\left(x \right)} " data-equation-content=" \displaystyle f=\sin{\left(x \right)} " /> and <img class="equation_image" title=" \displaystyle g=e^{x} \cos{\left(x \right)} " src="/equation_images/%20%5Cdisplaystyle%20g%3De%5E%7Bx%7D%20%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%20" alt="LaTeX: \displaystyle g=e^{x} \cos{\left(x \right)} " data-equation-content=" \displaystyle g=e^{x} \cos{\left(x \right)} " /> and using the product rule with <img class="equation_image" title=" \displaystyle f=\sin{\left(x \right)} \implies f'=\cos{\left(x \right)} " src="/equation_images/%20%5Cdisplaystyle%20f%3D%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20%5Cimplies%20f%27%3D%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%20" alt="LaTeX: \displaystyle f=\sin{\left(x \right)} \implies f'=\cos{\left(x \right)} " data-equation-content=" \displaystyle f=\sin{\left(x \right)} \implies f'=\cos{\left(x \right)} " /> . This leaves g as <img class="equation_image" title=" \displaystyle g = e^{x} \cos{\left(x \right)} " src="/equation_images/%20%5Cdisplaystyle%20g%20%3D%20e%5E%7Bx%7D%20%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%20" alt="LaTeX: \displaystyle g = e^{x} \cos{\left(x \right)} " data-equation-content=" \displaystyle g = e^{x} \cos{\left(x \right)} " /> which also requires the product rule. Pushing down in the new product rule <img class="equation_image" title=" \displaystyle f=e^{x} \implies f'=e^{x} " src="/equation_images/%20%5Cdisplaystyle%20f%3De%5E%7Bx%7D%20%5Cimplies%20f%27%3De%5E%7Bx%7D%20" alt="LaTeX: \displaystyle f=e^{x} \implies f'=e^{x} " data-equation-content=" \displaystyle f=e^{x} \implies f'=e^{x} " /> and <img class="equation_image" title=" \displaystyle g=\cos{\left(x \right)} \implies g'=- \sin{\left(x \right)} " src="/equation_images/%20%5Cdisplaystyle%20g%3D%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%20%5Cimplies%20g%27%3D-%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20" alt="LaTeX: \displaystyle g=\cos{\left(x \right)} \implies g'=- \sin{\left(x \right)} " data-equation-content=" \displaystyle g=\cos{\left(x \right)} \implies g'=- \sin{\left(x \right)} " /> . Popping up a level gives <img class="equation_image" title=" \displaystyle g'=(\cos{\left(x \right)})(e^{x})+(e^{x})(- \sin{\left(x \right)}) " src="/equation_images/%20%5Cdisplaystyle%20g%27%3D%28%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%29%28e%5E%7Bx%7D%29%2B%28e%5E%7Bx%7D%29%28-%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%29%20" alt="LaTeX: \displaystyle g'=(\cos{\left(x \right)})(e^{x})+(e^{x})(- \sin{\left(x \right)}) " data-equation-content=" \displaystyle g'=(\cos{\left(x \right)})(e^{x})+(e^{x})(- \sin{\left(x \right)}) " /> Popping up again (Back to the original problem) gives <img class="equation_image" title=" \displaystyle f'=(\sin{\left(x \right)})(- e^{x} \sin{\left(x \right)} + e^{x} \cos{\left(x \right)})+(e^{x} \cos{\left(x \right)})(\cos{\left(x \right)})=- e^{x} \sin^{2}{\left(x \right)} + e^{x} \sin{\left(x \right)} \cos{\left(x \right)} + e^{x} \cos^{2}{\left(x \right)} " src="/equation_images/%20%5Cdisplaystyle%20f%27%3D%28%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%29%28-%20e%5E%7Bx%7D%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20%2B%20e%5E%7Bx%7D%20%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%29%2B%28e%5E%7Bx%7D%20%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%29%28%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%29%3D-%20e%5E%7Bx%7D%20%5Csin%5E%7B2%7D%7B%5Cleft%28x%20%5Cright%29%7D%20%2B%20e%5E%7Bx%7D%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%20%2B%20e%5E%7Bx%7D%20%5Ccos%5E%7B2%7D%7B%5Cleft%28x%20%5Cright%29%7D%20" alt="LaTeX: \displaystyle f'=(\sin{\left(x \right)})(- e^{x} \sin{\left(x \right)} + e^{x} \cos{\left(x \right)})+(e^{x} \cos{\left(x \right)})(\cos{\left(x \right)})=- e^{x} \sin^{2}{\left(x \right)} + e^{x} \sin{\left(x \right)} \cos{\left(x \right)} + e^{x} \cos^{2}{\left(x \right)} " data-equation-content=" \displaystyle f'=(\sin{\left(x \right)})(- e^{x} \sin{\left(x \right)} + e^{x} \cos{\left(x \right)})+(e^{x} \cos{\left(x \right)})(\cos{\left(x \right)})=- e^{x} \sin^{2}{\left(x \right)} + e^{x} \sin{\left(x \right)} \cos{\left(x \right)} + e^{x} \cos^{2}{\left(x \right)} " /> </p> </p>