Generate Math Exams and Quizzes in LaTeX and pdf formats

Identifying \(\displaystyle f=- 2 x - 9\) and \(\displaystyle g=\left(7 - 3 x\right) \sin{\left(x \right)}\) and using the product rule with \(\displaystyle f=- 2 x - 9 \implies f'=-2\). This leaves g as \(\displaystyle g = \left(7 - 3 x\right) \sin{\left(x \right)}\) which also requires the product rule. Pushing down in the new product rule \(\displaystyle f=\sin{\left(x \right)} \implies f'=\cos{\left(x \right)}\) and \(\displaystyle g=7 - 3 x \implies g'=-3\). Popping up a level gives \(\displaystyle g'=(7 - 3 x)(\cos{\left(x \right)})+(\sin{\left(x \right)})(-3)\)Popping up again (Back to the original problem) gives \(\displaystyle f'=(- 2 x - 9)(\left(7 - 3 x\right) \cos{\left(x \right)} - 3 \sin{\left(x \right)})+(\left(7 - 3 x\right) \sin{\left(x \right)})(-2)=\left(7 - 3 x\right) \left(- 2 x - 9\right) \cos{\left(x \right)} + \left(6 x - 14\right) \sin{\left(x \right)} + \left(6 x + 27\right) \sin{\left(x \right)}\)

Download \(\LaTeX\)

\begin{question}Find the derivative of $y = (- 2 x - 9)(\sin{\left(x \right)})(7 - 3 x)$.
    \soln{9cm}{Identifying $f=- 2 x - 9$ and $g=\left(7 - 3 x\right) \sin{\left(x \right)}$ and using the product rule with $f=- 2 x - 9 \implies f'=-2$. This leaves g as $g = \left(7 - 3 x\right) \sin{\left(x \right)}$ which also requires the product rule. Pushing down in the new product rule $f=\sin{\left(x \right)} \implies f'=\cos{\left(x \right)}$ and $g=7 - 3 x \implies g'=-3$. Popping up a level gives $g'=(7 - 3 x)(\cos{\left(x \right)})+(\sin{\left(x \right)})(-3)$Popping up again (Back to the original problem) gives $f'=(- 2 x - 9)(\left(7 - 3 x\right) \cos{\left(x \right)} - 3 \sin{\left(x \right)})+(\left(7 - 3 x\right) \sin{\left(x \right)})(-2)=\left(7 - 3 x\right) \left(- 2 x - 9\right) \cos{\left(x \right)} + \left(6 x - 14\right) \sin{\left(x \right)} + \left(6 x + 27\right) \sin{\left(x \right)}$}

\end{question}

Download Question and Solution Environment\(\LaTeX\)

\documentclass{article}
\usepackage{tikz}
\usepackage{amsmath}
\usepackage[margin=2cm]{geometry}
\usepackage{tcolorbox}

\newcounter{ExamNumber}
\newcounter{questioncount}
\stepcounter{questioncount}

\newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}}
\renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}}

\newif\ifShowSolution
\newcommand{\soln}[2]{%
\ifShowSolution%
\noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else%
\vspace{#1}%
\fi%
}%
\newcommand{\hideifShowSolution}[1]{%
\ifShowSolution%
%
\else%
#1%
\fi%
}%
\everymath{\displaystyle}
\ShowSolutiontrue

\begin{document}\begin{question}(10pts) The question goes here!
    \soln{9cm}{The solution goes here.}

\end{question}\end{document}

HTML for Canvas

<p> <p>Find the derivative of  <img class="equation_image" title=" \displaystyle y = (- 2 x - 9)(\sin{\left(x \right)})(7 - 3 x) " src="/equation_images/%20%5Cdisplaystyle%20y%20%3D%20%28-%202%20x%20-%209%29%28%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%29%287%20-%203%20x%29%20" alt="LaTeX:  \displaystyle y = (- 2 x - 9)(\sin{\left(x \right)})(7 - 3 x) " data-equation-content=" \displaystyle y = (- 2 x - 9)(\sin{\left(x \right)})(7 - 3 x) " /> .</p> </p>

HTML for Canvas

<p> <p>Identifying  <img class="equation_image" title=" \displaystyle f=- 2 x - 9 " src="/equation_images/%20%5Cdisplaystyle%20f%3D-%202%20x%20-%209%20" alt="LaTeX:  \displaystyle f=- 2 x - 9 " data-equation-content=" \displaystyle f=- 2 x - 9 " />  and  <img class="equation_image" title=" \displaystyle g=\left(7 - 3 x\right) \sin{\left(x \right)} " src="/equation_images/%20%5Cdisplaystyle%20g%3D%5Cleft%287%20-%203%20x%5Cright%29%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20" alt="LaTeX:  \displaystyle g=\left(7 - 3 x\right) \sin{\left(x \right)} " data-equation-content=" \displaystyle g=\left(7 - 3 x\right) \sin{\left(x \right)} " />  and using the product rule with  <img class="equation_image" title=" \displaystyle f=- 2 x - 9 \implies f'=-2 " src="/equation_images/%20%5Cdisplaystyle%20f%3D-%202%20x%20-%209%20%5Cimplies%20f%27%3D-2%20" alt="LaTeX:  \displaystyle f=- 2 x - 9 \implies f'=-2 " data-equation-content=" \displaystyle f=- 2 x - 9 \implies f'=-2 " /> . This leaves g as  <img class="equation_image" title=" \displaystyle g = \left(7 - 3 x\right) \sin{\left(x \right)} " src="/equation_images/%20%5Cdisplaystyle%20g%20%3D%20%5Cleft%287%20-%203%20x%5Cright%29%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20" alt="LaTeX:  \displaystyle g = \left(7 - 3 x\right) \sin{\left(x \right)} " data-equation-content=" \displaystyle g = \left(7 - 3 x\right) \sin{\left(x \right)} " />  which also requires the product rule. Pushing down in the new product rule  <img class="equation_image" title=" \displaystyle f=\sin{\left(x \right)} \implies f'=\cos{\left(x \right)} " src="/equation_images/%20%5Cdisplaystyle%20f%3D%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20%5Cimplies%20f%27%3D%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%20" alt="LaTeX:  \displaystyle f=\sin{\left(x \right)} \implies f'=\cos{\left(x \right)} " data-equation-content=" \displaystyle f=\sin{\left(x \right)} \implies f'=\cos{\left(x \right)} " />  and  <img class="equation_image" title=" \displaystyle g=7 - 3 x \implies g'=-3 " src="/equation_images/%20%5Cdisplaystyle%20g%3D7%20-%203%20x%20%5Cimplies%20g%27%3D-3%20" alt="LaTeX:  \displaystyle g=7 - 3 x \implies g'=-3 " data-equation-content=" \displaystyle g=7 - 3 x \implies g'=-3 " /> . Popping up a level gives  <img class="equation_image" title=" \displaystyle g'=(7 - 3 x)(\cos{\left(x \right)})+(\sin{\left(x \right)})(-3) " src="/equation_images/%20%5Cdisplaystyle%20g%27%3D%287%20-%203%20x%29%28%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%29%2B%28%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%29%28-3%29%20" alt="LaTeX:  \displaystyle g'=(7 - 3 x)(\cos{\left(x \right)})+(\sin{\left(x \right)})(-3) " data-equation-content=" \displaystyle g'=(7 - 3 x)(\cos{\left(x \right)})+(\sin{\left(x \right)})(-3) " /> Popping up again (Back to the original problem) gives  <img class="equation_image" title=" \displaystyle f'=(- 2 x - 9)(\left(7 - 3 x\right) \cos{\left(x \right)} - 3 \sin{\left(x \right)})+(\left(7 - 3 x\right) \sin{\left(x \right)})(-2)=\left(7 - 3 x\right) \left(- 2 x - 9\right) \cos{\left(x \right)} + \left(6 x - 14\right) \sin{\left(x \right)} + \left(6 x + 27\right) \sin{\left(x \right)} " src="/equation_images/%20%5Cdisplaystyle%20f%27%3D%28-%202%20x%20-%209%29%28%5Cleft%287%20-%203%20x%5Cright%29%20%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%20-%203%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%29%2B%28%5Cleft%287%20-%203%20x%5Cright%29%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%29%28-2%29%3D%5Cleft%287%20-%203%20x%5Cright%29%20%5Cleft%28-%202%20x%20-%209%5Cright%29%20%5Ccos%7B%5Cleft%28x%20%5Cright%29%7D%20%2B%20%5Cleft%286%20x%20-%2014%5Cright%29%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20%2B%20%5Cleft%286%20x%20%2B%2027%5Cright%29%20%5Csin%7B%5Cleft%28x%20%5Cright%29%7D%20" alt="LaTeX:  \displaystyle f'=(- 2 x - 9)(\left(7 - 3 x\right) \cos{\left(x \right)} - 3 \sin{\left(x \right)})+(\left(7 - 3 x\right) \sin{\left(x \right)})(-2)=\left(7 - 3 x\right) \left(- 2 x - 9\right) \cos{\left(x \right)} + \left(6 x - 14\right) \sin{\left(x \right)} + \left(6 x + 27\right) \sin{\left(x \right)} " data-equation-content=" \displaystyle f'=(- 2 x - 9)(\left(7 - 3 x\right) \cos{\left(x \right)} - 3 \sin{\left(x \right)})+(\left(7 - 3 x\right) \sin{\left(x \right)})(-2)=\left(7 - 3 x\right) \left(- 2 x - 9\right) \cos{\left(x \right)} + \left(6 x - 14\right) \sin{\left(x \right)} + \left(6 x + 27\right) \sin{\left(x \right)} " /> </p> </p>