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Questions: Algebra BusinessCalculus
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Find the derivative \(\displaystyle f(x) = \frac{- 5 x^{\frac{2}{3}} - 4 x^{\frac{1}{3}} + 2 x}{x^{\frac{1}{3}}}\)
Using termwise division gives \(\displaystyle f(x) = 2 x^{\frac{2}{3}} - 5 x^{\frac{1}{3}} - 4\). Now the power rule for derivatives can be used instead of the quotient rule. This gives \begin{equation*}f'(x) = \frac{4}{3 \sqrt[3]{x}} - \frac{5}{3 x^{\frac{2}{3}}} \end{equation*}
\begin{question}Find the derivative $f(x) = \frac{- 5 x^{\frac{2}{3}} - 4 x^{\frac{1}{3}} + 2 x}{x^{\frac{1}{3}}}$ \soln{9cm}{Using termwise division gives $f(x) = 2 x^{\frac{2}{3}} - 5 x^{\frac{1}{3}} - 4$. Now the power rule for derivatives can be used instead of the quotient rule. This gives \begin{equation*}f'(x) = \frac{4}{3 \sqrt[3]{x}} - \frac{5}{3 x^{\frac{2}{3}}} \end{equation*}} \end{question}
\documentclass{article} \usepackage{tikz} \usepackage{amsmath} \usepackage[margin=2cm]{geometry} \usepackage{tcolorbox} \newcounter{ExamNumber} \newcounter{questioncount} \stepcounter{questioncount} \newenvironment{question}{{\noindent\bfseries Question \arabic{questioncount}.}}{\stepcounter{questioncount}} \renewcommand{\labelenumi}{{\bfseries (\alph{enumi})}} \newif\ifShowSolution \newcommand{\soln}[2]{% \ifShowSolution% \noindent\begin{tcolorbox}[colframe=blue,title=Solution]#2\end{tcolorbox}\else% \vspace{#1}% \fi% }% \newcommand{\hideifShowSolution}[1]{% \ifShowSolution% % \else% #1% \fi% }% \everymath{\displaystyle} \ShowSolutiontrue \begin{document}\begin{question}(10pts) The question goes here! \soln{9cm}{The solution goes here.} \end{question}\end{document}
<p> <p>Find the derivative <img class="equation_image" title=" \displaystyle f(x) = \frac{- 5 x^{\frac{2}{3}} - 4 x^{\frac{1}{3}} + 2 x}{x^{\frac{1}{3}}} " src="/equation_images/%20%5Cdisplaystyle%20f%28x%29%20%3D%20%5Cfrac%7B-%205%20x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%20-%204%20x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%2B%202%20x%7D%7Bx%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%20" alt="LaTeX: \displaystyle f(x) = \frac{- 5 x^{\frac{2}{3}} - 4 x^{\frac{1}{3}} + 2 x}{x^{\frac{1}{3}}} " data-equation-content=" \displaystyle f(x) = \frac{- 5 x^{\frac{2}{3}} - 4 x^{\frac{1}{3}} + 2 x}{x^{\frac{1}{3}}} " /> </p> </p>
<p> <p>Using termwise division gives <img class="equation_image" title=" \displaystyle f(x) = 2 x^{\frac{2}{3}} - 5 x^{\frac{1}{3}} - 4 " src="/equation_images/%20%5Cdisplaystyle%20f%28x%29%20%3D%202%20x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%20-%205%20x%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20-%204%20" alt="LaTeX: \displaystyle f(x) = 2 x^{\frac{2}{3}} - 5 x^{\frac{1}{3}} - 4 " data-equation-content=" \displaystyle f(x) = 2 x^{\frac{2}{3}} - 5 x^{\frac{1}{3}} - 4 " /> . Now the power rule for derivatives can be used instead of the quotient rule. This gives
<img class="equation_image" title=" f'(x) = \frac{4}{3 \sqrt[3]{x}} - \frac{5}{3 x^{\frac{2}{3}}} " src="/equation_images/%20f%27%28x%29%20%3D%20%5Cfrac%7B4%7D%7B3%20%5Csqrt%5B3%5D%7Bx%7D%7D%20-%20%5Cfrac%7B5%7D%7B3%20x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%7D%20%20" alt="LaTeX: f'(x) = \frac{4}{3 \sqrt[3]{x}} - \frac{5}{3 x^{\frac{2}{3}}} " data-equation-content=" f'(x) = \frac{4}{3 \sqrt[3]{x}} - \frac{5}{3 x^{\frac{2}{3}}} " /> </p> </p>